Which of the following functions is the unique solution of the IBVP 0 < x < 2T, t> 0 AUTI u(0, t) = u(2π, t) = 0, t> 0 u(x,0) = sin x 2 sin 4x, T Select one: OA. u(x, t) = sin re OB. u(x, t) = 2 sin ze OC. u(x, t) = sin ze 4t OD. u(x, t) = sin ze 8t 4t E. u(x, t) = 2 sin ze 16t 4t 0 < x < 2. 2 sin 4xe 16t sin 4xe-32t 2 sin 4xe 16t 2 sin 4re-64t sin 4xe 64t پر
Which of the following functions is the unique solution of the IBVP 0 < x < 2T, t> 0 AUTI u(0, t) = u(2π, t) = 0, t> 0 u(x,0) = sin x 2 sin 4x, T Select one: OA. u(x, t) = sin re OB. u(x, t) = 2 sin ze OC. u(x, t) = sin ze 4t OD. u(x, t) = sin ze 8t 4t E. u(x, t) = 2 sin ze 16t 4t 0 < x < 2. 2 sin 4xe 16t sin 4xe-32t 2 sin 4xe 16t 2 sin 4re-64t sin 4xe 64t پر
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Which of the following functions is the unique solution of the IBVP
Ut = 4uzz, 0<x< 2π, t > 0
u(0, t) = u(2n, t) = 0, t> 0
u(x,0) = sinx - 2 sin 4x,
Select one:
A. u(x, t)
B. u(x, t) = 2 sin re
sin re
41
sin re
8t
16t
Cu(x, t)
D. u(x, t) = sin ze
E u(x, t) = 2 sin æe 4t
0<x< 2π.
2 sin 4xe 16t
sin 4xe-32t
2 sin 4xe
2 sin 4xe
16t
64t
sin 4xe 64t
R
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