Which of the following functions has both a vertical reflection and a horizontal reflection? Of(x) = cos(x) – 1 - Of(x) = -sin[-5(x -45°)] Of(x) = cos [(x + 360°)] Of(x) = sin(-2x) - 3 -

Q: Match each expression with the appropriate formula that would be used for simplification. sin 8x +…

A: Solution:-

Q: sin (x) – cos²(x) Show that 1 F COS %3D CSC (x)

A:

Q: 1 Let f(x) = (5 sin x + 8 cos a)tan f'(x) =

A: NOTE: Refresh your page if you can't see any equations. . take derivative use the product rule for…

Q: f(x)=tan(x)-1/sec(x) Simplify the expression for f(x) by writing it in terms of sin(x) and cos(x),…

A:

Q: 4) a) Determine the simplified expression for the 623rd derivative for the function f(x) =cos(2x)…

A: a)   fx=cos2x+sin2π     =cos2x+0      = cos2x

Q: Wouldn't tan(x+pi)-(-sin(x)) yield tan(x+pi) + sin(x)) instead of tan(x+pi) - sin(x))?

A: Yes , there is a mistake on that question. I give u correct solution .  tan(x + π) - cos( x + (π/2))…

Q: (cos(x)cot(x)/1-sin(x))-1=csc(x)

A: We have given (cos(x)cot(x)/1-sin(x))-1=csc(x)

Q: (b) Evaluate A () a().

A: We have to evaluate  Delta( Sinx / x2 + 2x - 1 ) which is the laplacian or double derivative of the…

Q: (cos A + sin A)/(cos A - sin A) = (1+ sin(2A))/ cos(2A)

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: Explain how to transform sin x into the function f(x) = -sin x. 4

A: To transform the function sin(x) into the function f(x) =-14sin x, we can apply a vertical stretch…

Q: If f(x) = sin(2x) + sin(4x) + sin(6x), determine the fundamental period. %3D

A:

Q: If f (x) = - cos(x), then f (10) (x) is equal to (A) - sin (x) ® -cos(x) © sin(x) D cos(x)

A:

Q: [(2tan(x)/1+sec(x))+(2+2sec(x)/tan(x))]=4csc(x)

A: Consider the left hand side,

Q: 4) Verify. cos²(x)[1 C. – tan²(x)] = cos(2x)

A:

Q: (3) (a) Express cos(3r) in terms of sinx and cosr. (b) Prove that -cosz 1+cosI tan %3D (c) Sketch…

A: (3)  (a)  express cos(3x) in terms of cosx and sin x.       (b)  prove that 1-cos x1+cos x=tan2 x2…

Q: Find sin(x/2) =  cos(x/2) =  tan(x/2) =  Given tan(x) = 2sqrt2    0 degrees < x< 90 degrees

A:

Q: Show that sin²(x) cos(x) = sec(x) – cos(x)

A: We need to show the following. So,         Manipulating right side=secx-cosx=1-cos2xcosx=sin2xcosx