Which of the following functions find the count of even numbers enclosed within double quotes in an array with 7 ? a. int countEven( char *a[]) { int i,j,nump 0;for (j = 0; j < 7; j++) { if(atoi(a[j])%2!=0){nump+=1;} }return %3D nump;} b. int countEven( char *a[]) { int i,j,nump 0;for (j = 0; j < 7; ++j) { if(atoi(a[j])%2=3D0){nump++;} }return %3D nump;} c. int countEven( char *a[]) { int i,j,nump = 0;for (j = 0; j < 7; j++) { if(atoi(a[j-1])%2=D%3D0){nump++;} }return nump;} d. int countEven( char *a[]) { int i,j,nump 0; for (j = 0; j < 7; j++) { if(atoi(a[j])%2=3D0){nump+%3Dnump;} }return nump;} e, int countEven( char *a[]) { int ij,nump = 0;for (j = 0; j < 7; j++) { if(atoi(a[j])%2!=0){nump++;} }return nump;} %3D

Which of the following functions find the count of even numbers enclosed within double quotes in an array with 7 ? a. int countEven( char a[]) { int i,j,nump 0;for (j = 0; j < 7; j++) { if(atoi(a[j])%2!=0){nump+=1;} }return %3D nump;} b. int countEven( char a[]) { int i,j,nump 0;for (j = 0; j < 7; ++j) { if(atoi(a[j])%2=3D0){nump++;} }return %3D nump;} c. int countEven( char a[]) { int i,j,nump = 0;for (j = 0; j < 7; j++) { if(atoi(a[j-1])%2=D%3D0){nump++;} }return nump;} d. int countEven( char a[]) { int i,j,nump 0; for (j = 0; j < 7; j++) { if(atoi(a[j])%2=3D0){nump+%3Dnump;} }return nump;} e, int countEven( char *a[]) { int ij,nump = 0;for (j = 0; j < 7; j++) { if(atoi(a[j])%2!=0){nump++;} }return nump;} %3D

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

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Which of the following functions find the count of even numbers enclosed within double quotes in an array with 7 ?
a. int countEven( char *a[]) { int i,j,nump
0;for (j = 0; j < 7; j++) { if(atoi(a[j])%2!=0){nump+=1;} }return
%3D
nump;}
b. int countEven( char *a[]) { int i,j,nump
0;for (j = 0; j < 7; ++j) { if(atoi(a[j])%2=3D0){nump++;} }return
%3D
nump;}
c. int countEven( char *a[]) { int i,j,nump = 0;for (j = 0; j < 7; j++) { if(atoi(a[j-1])%2=D%3D0){nump++;} }return
nump;}
d. int countEven( char *a[]) { int i,j,nump 0; for (j = 0; j < 7; j++) { if(atoi(a[j])%2=3D0){nump+%3Dnump;}
}return nump;}
e, int countEven( char *a[]) { int ij,nump = 0;for (j = 0; j < 7; j++) { if(atoi(a[j])%2!=0){nump++;} }return
nump;}
%3D

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