Which of the following functions are solutions to the 1-D wave equation? a²f Ət² 4 a²f 0х2 f = cos(2x +t) Of=sin(x - 2t) Of=sin(2x - t) f = cos(x + 2t) Of=tan(x - 2t)

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A: Solution6 sin2x+cos 2x+1=0we know cos 2 x= 1-2 sin2xput this value in the given equation,6 sin2 x+…

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A: Explanation of the answer is as follows

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A: Since you have asked multiple questions, we will solve the first Question for you. If you want any…

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A: Prove :

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Q: a) 2(sin x)² - 1 = 0 [0,2π]

A: a) 2(sin⁡x)2−1=0[0,2π]

Q: -1

A: Given,