Answered: Which of the following forces does…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

Which of the following forces does methanol (CH3-OH) exhibit? Select all that apply.

hydrogen bonding

London forces

dipole-dipole attractions

Expert Solution

Introduction

Hydrogen bonding -

Electrostatic force of attraction.
It exists between hydrogen atom that is bonded to more electronegative atom and another electronegative atom.
Strong IMF.

Types-

Intramolecular H-bonding (within molecule)
Intermolecular H-bonding (between molecules)

London forces -

Also known as London dispersion forces or Van der Waals forces.
These are the temporary attractive forces that occur due to motion of electrons.
Exists between polar, non-polar, ions , noble gases.
Bond strength is high.
Molecule with instantaneous dipole moment show dipole-dipole attractions.

Dipole-dipole attractions

Electrostatic interaction and attractive forces between polar molecule.
Partial positive end of polar molecule is attracted tp partial negative end of another polar molecule.
Occur due to unequal sharing of electrons
Bond strength is weak.
Molecule with permanent dipole moment show dipole-dipole attractions.

Step 2

London forces exists between all types of molecules.

It has hydrogen boding between H attached to electronegative O atom and oxygen of another methanol molecule.
This is intermolecular hydrogen bonding.

Methanol is a polar molecule.
It is permanent dipole moment.
Dipole -dipole attraction is between partial positive H atom and partial negative oxygen atom.

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions