Which of the following equation is symmetric with respect to z- aris and y-azis. O 2+yl=64 O z4- =64 O - = 121 O z6 - = 88 8-y = 121 %3D %3D %3D Factor completely using the difference of cubes pattern : 216r- 64y O (6x + 4y)(36z² + 24ry + 16y) O (6r 4y)(36z - 24zy + 64y) O (6r 4y)(36z2 + 24ry - 64y³) O (6x 4y) (36r + 24ry + 16y³) O (6x + 4y)(24r? + 24ry + 16y³) 3V4+4v3 8V4- 33 Rationalize the denominator: 132 + 35V12 229 132 + 41/12 247 132 + 41V12 229 O60+41/12 229 O132 + 41v12 283

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Which of the following equation is symmetric with respect to z
azis and y-azis.
O 2 + yll =64
O 4-=D64
O - = 121
O 26-y = 88
O z- = 121
Factor completely using the difference of cubes pattern : 216x- 64y
O (6x +4y)(36z² + 24ry+ 16y³)
O (6- 4y)(36z - 24ry + 64y')
O (62 - 4y)(36r² + 24ry- 64y)
O (6x – 4y)(36.r? + 24ry + 16y²)
O (6x + 4y)(24a? + 24ry + 16y)
3V4 + 4v3
Rationalize the denominator:
8/4- 33
132 +35v12
229
132 + 41/12
247
132 + 41V12
229
60 + 41V12
229
132 + 41/12
283
Transcribed Image Text:Which of the following equation is symmetric with respect to z azis and y-azis. O 2 + yll =64 O 4-=D64 O - = 121 O 26-y = 88 O z- = 121 Factor completely using the difference of cubes pattern : 216x- 64y O (6x +4y)(36z² + 24ry+ 16y³) O (6- 4y)(36z - 24ry + 64y') O (62 - 4y)(36r² + 24ry- 64y) O (6x – 4y)(36.r? + 24ry + 16y²) O (6x + 4y)(24a? + 24ry + 16y) 3V4 + 4v3 Rationalize the denominator: 8/4- 33 132 +35v12 229 132 + 41/12 247 132 + 41V12 229 60 + 41V12 229 132 + 41/12 283
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