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Which of the following electrons indicated with an asterisk will be the lowest in energy? 2s 1s 1s 1s 1s (H) (He) (Li*) (Li) A B D O A

Which of the following electrons indicated with an asterisk will be the lowest in energy? 2s 1s 1s 1s 1s (H) (He) (Li*) (Li) A B D O A

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** Which of the following electrons indicated with an asterisk will be the lowest in energy? **Electron Configurations:** - **A:** - Electron Configuration: \(1s^*\) - Element: \( \text{H} \) (Hydrogen) - **B:** - Electron Configuration: \(1s^*\) - Element: \( \text{He} \) (Helium) - **C:** - Electron Configuration: \(1s^*\) - Element: \( \text{Li}^+ \) (Lithium cation) - **D:** - Electron Configuration: \(2s^*\) - Element: \( \text{Li} \) (Lithium) **Answer Options:** - \( \text{A} \) - \( \text{B} \) - \( \text{C} \) - \( \text{D} \) **Explanation:** The diagram displays four electron configurations, each representing a different element or ion, with an electron indicated by an asterisk. The configurations show electrons in either the 1s or 2s orbital. The goal is to determine which electron (marked by an asterisk) resides in the lowest energy state.
Transcribed Image Text:**Question:** Which of the following electrons indicated with an asterisk will be the lowest in energy? **Electron Configurations:** - **A:** - Electron Configuration: \(1s^*\) - Element: \( \text{H} \) (Hydrogen) - **B:** - Electron Configuration: \(1s^*\) - Element: \( \text{He} \) (Helium) - **C:** - Electron Configuration: \(1s^*\) - Element: \( \text{Li}^+ \) (Lithium cation) - **D:** - Electron Configuration: \(2s^*\) - Element: \( \text{Li} \) (Lithium) **Answer Options:** - \( \text{A} \) - \( \text{B} \) - \( \text{C} \) - \( \text{D} \) **Explanation:** The diagram displays four electron configurations, each representing a different element or ion, with an electron indicated by an asterisk. The configurations show electrons in either the 1s or 2s orbital. The goal is to determine which electron (marked by an asterisk) resides in the lowest energy state.
Expert Solution
Step 1

The negatively charged electrons are attracted by the positive charge of the nucleus. As the number of protons in the nucleus increases the positive charge in the nucleus also increases. 

The number of proton in the given nucleus is as follows:

atom number of proton
H 1
He 2
Li 3
Li+ 3

 

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