7 **Question:** Which of the following electrons indicated with an asterisk will be the lowest in energy?**Electron Configurations:**- **A:** - Electron Configuration: \(1s^*\) - Element: \( \text{H} \) (Hydrogen)- **B:** - Electron Configuration: \(1s^*\) - Element: \( \text{He} \) (Helium)- **C:** - Electron Configuration: \(1s^*\) - Element: \( \text{Li}^+ \) (Lithium cation)- **D:** - Electron Configuration: \(2s^*\) - Element: \( \text{Li} \) (Lithium)**Answer Options:**- \( \text{A} \)- \( \text{B} \)- \( \text{C} \)- \( \text{D} \)**Explanation:**The diagram displays four electron configurations, each representing a different element or ion, with an electron indicated by an asterisk. The configurations show electrons in either the 1s or 2s orbital. The goal is to determine which electron (marked by an asterisk) resides in the lowest energy state.

Answered: Which of the following electrons…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The negatively charged electrons are attracted by the positive charge of the nucleus. As the number of protons in the nucleus increases the positive charge in the nucleus also increases.

The number of proton in the given nucleus is as follows:

atom	number of proton
H	1
He	2
Li	3
Li+	3

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