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Q: Methanoic acid (HMeth) has a Ka of 1.78 * 10-6, so what is the pOH of a 0.23 M NaMethsolution?
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A: We are given:[H3O+] = 5.112 x 10-13To find: pOH
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- what is the dissociation reaction for the compound below in an aqueous solution? write NR after the rection arrow. CH3OH (aq) -->Caclulate the pOH for a 7.58 x 10 - 6 M H4SeO6 solution assuming complete disassociation18 1) OH- 2) H+ or OH 7 2 4 3 Br₂ CH₂l₂, Zn/Cu 15 16 14 17 17 1) 03 2) (CH3)2S H₂O, H₂SO4 1) Hg(OAc)2, ROH 2) NaBHд 1) Br₂, H₂O OsO4, H₂O₂ 1) Hg(OAc)2, H₂O 2) NaBH4 2) H* or OH- 1) RCOOOH 1) BH₂, THF 2) H₂O₂, OH, H₂O HBr ROOR, HBr H₂, Pd/Pt/Ni 13 03 H₂O₂ 12 11 10 5 CHCl3, NaOH, H₂O warm MnO4, OH or H+ cold MnO4, OH or H* 6 6 7 80
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