Which of the following can residual analysis be used for: to test for interactions to test for multicollinearity to test for autocorrelation to test for extrapolation
Q: Which model would you select? Explain your choice and the criteria used to reach your decision.
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Q: Number of Facilities Number 9 11 16 21 27 30 Average Distance (miles) 1.67 1.11 0.83 0.63 0.52 0.46…
A: Number of Facilities Average Distance 9 1.67 11 1.11 16 0.83 21 0.63 27 0.52 30 0.46…
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A: given 36.45, 67.90, 38.77, 42.18, 26.72, 50.77, 39.30, 49.71
Q: b) the correlation coefficient :of this data is
A: here use basic of Correlation coefficient
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A: Given: q=kCn C q 82.5 337.7 46.2 207.6 26.2 123.8 17.7 88.2 13.4 68.3 6.8 35.8
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Q: The Minitab output shown below was obtained by using paired data consisting of weights (in lb) of 27…
A: Given :
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- A study of emergency service facilities investigated the relationship between the number of facilities and the average distance traveled to provide the emergency service. The following table gives the data collected. Average Distance Number of Facilities (miles) 1.67 11 1.11 16 0.82 21 0.62 27 0.50 30 0.47 (a) Develop a scatter diagram for these data, treating average distance traveled as the dependent variable. 1.8 T 35 1.8 1.8 1.6- 1.6- 1.6 30 1.4 1.4 1.4 1.2 25 1.2 1.2 1. 1. 1. 20 0.8 0.8 0.8 0.6 15 0.6 0.6- 0.4 0.4 0.4 10 0.2 0.2 0.2 0. 5 0. 0. 10 15 20 25 30 35 0. 0.2 0.4 0.6 0.8 1. 1.2 1.4 1.6 1.8 5 10 15 20 25 30 35 10 15 20 25 30 35 Number Distance Number Number (b) Does a simple linear regression model appear to be appropriate? Explain. O Yes, the scatter diagram suggests that there is a linear relationship. O No, the scatter diagram suggests that there is a curvilinear relationship. O No, the scatter diagram suggests that there is no relationship. (c) Develop an estimated…Consider a regression analysis with n = 47 and three potential independent variables. Suppose that one of the independent variables has a correlation of 0.95 with the dependent variable. Does this imply that this independent variable will have a very large Student’s t statistic in the regression analysis with all three predictor variables?The weights (in pounds) of 6 vehicles and the variability of their braking distances (in feet) when stopping on a dry surface are shown in the table. Can you conclude that there is a significant linear correlation between vehicle weight and variability in braking distance on a dry surface? Use α=0.01. Weight, x 5920 5370 6500 5100 5890 4800 Variability in 1.76 1.91 1.50 braking distance, y EEE Click here to view a table of critical values for Student's t-distribution. Setup the hypothesis for the test. Ho: P Ha: P 0 0 1.86 1.62 1.67 M
- Are MRI count and IQ linearly related? Because the correlation coefficient for females is negative/positiveand the absolute value of this correlation coefficient, enter your response here#, is greater/not greater than enter your response here#, the critical value for the female data set,no/a positive/a negativerelation exists between MRI count and IQ for females. Because the correlation coefficient for males is negative/positive and the absolute value of this correlation coefficient, enter your response here#, is greater/not greater than the critical value for the male data set, enter your response here#,no/a positive/a negative relation exists between MRI count and IQ for males. (Round to three decimal places as needed.) Critical value table 3 0.997 4 0.950 5 0.878 6 0.811 7 0.754 8 0.707 9 0.666 10 0.632 11 0.602 12 0.576 13 0.553 14 0.532 15 0.514 16 0.497 17 0.482 18 0.468 19 0.456 20 0.444 21 0.433 22 0.423 23 0.413 24 0.404 25 0.396 26 0.388 27 0.381 28 0.374…Solve the second question in regression analysisFind the equation of the regression that model the relationship between the weight of mail and number of order using HYPERBOLIC EQUATION. Compute for the correlation coefficient using PEARSON PRODUCT MOMENT CORRELATION COEFFICIENT (PPMCC).
- 28The following output is from a multiple regression analysis that was run on the variables FEARDTH (fear of death) IMPORTRE (importance of religion), AVOIDDTH (avoidance of death), LAS (meaning in life), and MATRLSM (materialistic attitudes). In the regression analysis, FEARDTH is the criterion variable (Y) and IMPORTRE,AVOIDDTH, LAS, and MATRLSM are the predictors (Xs). The SPSS output is provided below, followed by a number of questions. Descriptive Statistics Mean Std. Deviation N feardth 27.0798 8.08365 163 importre 5.8282 2.46104 163 avoiddth 18.5460 6.97633 163 Las 70.1288 9.89460 163 matrlsm 53.5552 10.21860 163 Model Variables Entered Variables Removed Method 1 matrlsm, avoiddth, importre, lasa . Enter a. All requested variables entered. b. Dependent Variable: feardth Model Summary Model R R Square Adjusted R Square…The Minitab output shown below was obtained by using paired data consisting of weights (in lb) of 31 cars and their highway fuel consumption amounts (in mi/gal). Along with the paired sample data, Minitab was also given a car weight of 4000 lb to be used for predicting the highway fuel consumption amount. Use the information provided in the display to determine the value of the linear correlation coefficient. (Be careful to correctly identify the sign of the correlation coefficient.) Given that there are 31 pairs of data, is there sufficient evidence to support a claim of linear correlation between the weights of cars and their highway fuel consumption amounts? Click the icon to view the Minitab display. The linear correlation coefficient is (Round to three decimal places as needed.) Is there sufficient evidence to support a claim of linear correlation? Yes O No Minitab output The regression equation is Highway = 50.8 -0.00508 Weight Predictor Coef SE Coef T P Constant 50.772 2.793…
- A study of emergency service facilities investigated the relationship between the number of facilities and the average distance traveled to provide the emergency service. The following table gives the data collected. Average Distance Number of Facilities (miles) 1.65 11 1.12 16 0.83 21 0.62 27 0.50 30 0.47 (a) Develop a scatter diagram for these data, treating average distance traveled as the dependent variable. 1.8 - 35- 1.8 1.8 1.6 1.6 1.6- 30 1.4- 1.4 1.4 1.2- 25 1.2 1.2 1. 1. 1. 20 0.8 0.8 0.8 0.6- 15 0.6- 0.6 0.4- 0.4 0.4 10 0.2 0.2 0.2 0. 5 0.- 0. 10 15 20 25 30 35 0. 0.2 0.4 0.6 0.8 1. 1.2 1.4 1.6 1.8 10 15 20 25 30 35 10 15 20 25 30 35 Number Distance Number Number (b) Does a simple linear regression model appear to be appropriate? Explain. O No, the scatter diagram suggests that there is no relationship. No, the scatter diagram suggests that there is a curvilinear relationship. O Yes, the scatter diagram suggests that there is a linear relationship. (c) Develop an estimated…This data table contians the listed prices and weights of the diamonds in 48 rings offered for sale in The Singapore Times. The prices are in Singapore dollars, with the weights in crats. Estimate the linear regression using weight as the explanatory variable and price as the response variable using the following two methods: a) Create a scatterplot with trendline (be sure to show the equation and R-square on the chart.) b) Use the Data Analysis Toolpak to do the work for you.