**Question:****Which of the following best explains why the synthetic route shown below would be unsuccessful?**\[ \text{HC} \equiv \text{C}^- \]\[ \begin{array}{lll}\quad \quad \quad \quad & 1) \quad \text{CH}_3\text{CH}_2\text{Br} & \\\quad \quad \quad \quad & \quad 2) \quad \text{NaNH}_2 & \quad \longrightarrow \quad \text{CH}_3\text{CH}_2\text{C} \equiv \text{CC}(\text{CH}_3)_3 \\\quad \quad \quad \quad & 3) \quad (\text{CH}_3)_3\text{CBr} & \end{array} \]**Options:**- \( \circ \) Reaction with sodium amide will result in formation of a primary alkyne- \( \circ \) The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide- \( \circ \) The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1- \( \circ \) Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2- \( \circ \) Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown

In step 1 alkynide anion is work as nucleophile and give substitution reaction. NaNH2 is a base…

Which of the following best explains why the synthetic route shown below would be unsuccessful? 1) CH;CH,Br HCEC: CH;CH,C=CC(CH3)a 2) NANH2 3) (CH3)3CBr O Reaction with sodium amide will result in formation of a primary alkyne O The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide O The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1 Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2 O Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown

Which of the following best explains why the synthetic route shown below would be unsuccessful? 1) CH;CH,Br HCEC: CH;CH,C=CC(CH3)a 2) NANH2 3) (CH3)3CBr O Reaction with sodium amide will result in formation of a primary alkyne O The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide O The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1 Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2 O Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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