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Which of the following are true in the given universe? Explain your answer. (a) (Vn € N) (n² + 3n+2 ≥ 0) True or False Why? (b) (!x € Z) (3x + 5 = 5x +9) True or False Why? (c) (3x € R) (y € R) (x² + y² = − 1) True or False Why?

Which of the following are true in the given universe? Explain your answer. (a) (Vn € N) (n² + 3n+2 ≥ 0) True or False Why? (b) (!x € Z) (3x + 5 = 5x +9) True or False Why? (c) (3x € R) (y € R) (x² + y² = − 1) True or False Why?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Which of the following are true in the given universe? Explain your answer. (a) (Vn € N) (n² + 3n+2 ≥ 0) True or False Why? (b) (!x € Z) (3x + 5 = 5x +9) True or False Why? (c) (3x € R) (y € R) (x² + y² = − 1) True or False Why?
Transcribed Image Text:Which of the following are true in the given universe? Explain your answer. (a) (Vn € N) (n² + 3n+2 ≥ 0) True or False Why? (b) (!x € Z) (3x + 5 = 5x +9) True or False Why? (c) (3x € R) (y € R) (x² + y² = − 1) True or False Why?
your answer, (a) (VxR) (x² + 6x +5≥ 0) True or False Why? Note: x²+6x+5 = (x+1)(x+5) Set Which of the following are true in the given universe? Explain x==2 EIR and (x+1)(x+5) =(-1)(3) <0 (b) (3x N) (2x + 3 = 6x + 7) True or False Why? Note: 2x+3=6x+7 ⇒ No XEN such that 2x+3=6x+7 ▸ • Set then (c) (3!x €Z (3!y €Z (x³ + y³ = −1) True or False Note: Z= Why? EZ € Z • Set x=-1 and y=0 then (-1)³ + (0)³ = -1 3 3 EZ and x=0 y=-1 3 (0)³ + (-1)³ = -1 3 -2x=3-7 4x=-4 x==1&N EZ | Note: Z = {0,11,1²,...} -3-2-10 23
Transcribed Image Text:your answer, (a) (VxR) (x² + 6x +5≥ 0) True or False Why? Note: x²+6x+5 = (x+1)(x+5) Set Which of the following are true in the given universe? Explain x==2 EIR and (x+1)(x+5) =(-1)(3) <0 (b) (3x N) (2x + 3 = 6x + 7) True or False Why? Note: 2x+3=6x+7 ⇒ No XEN such that 2x+3=6x+7 ▸ • Set then (c) (3!x €Z (3!y €Z (x³ + y³ = −1) True or False Note: Z= Why? EZ € Z • Set x=-1 and y=0 then (-1)³ + (0)³ = -1 3 3 EZ and x=0 y=-1 3 (0)³ + (-1)³ = -1 3 -2x=3-7 4x=-4 x==1&N EZ | Note: Z = {0,11,1²,...} -3-2-10 23
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