Which of the following are possible products of the partial hydrogenation, with two molecules of H2, of the following molecule? G 18:0 Fatty acid y 20:4 Fatty acid e 18:1 Fatty acid (Select all that apply.) 18:0, 20:0, 18:1 18:0, 20:2, 18:1 18:0, 20:3, 18:0
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![**Question:**
Which of the following are possible products of the partial hydrogenation, with two molecules of H₂, of the following molecule?
**Diagram:**
- The diagram shows a glycerol backbone linked to three different fatty acids:
- First chain: 18:0 Fatty acid
- Second chain: 20:4 Fatty acid
- Third chain: 18:1 Fatty acid
**Answer Choices:**
(Select all that apply.)
- [ ] 18:0, 20:0, 18:1
- [ ] 18:0, 20:2, 18:1
- [ ] 18:0, 20:3, 18:0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa550dac4-143c-4bad-9554-796cfbca8f57%2Fe03b06fe-7528-431e-9913-f86672abe172%2Fkvm5865_processed.jpeg&w=3840&q=75)
The numbers written in the fatty acid represents the number of carbon in the fatty acid followed by the degree of unsaturation of the fatty acid.
Given : Only 2 moles of H2 is used for hydrogenation.
Since the 1st fatty acid is having 0 degree of unsaturation.
Hence H2 will not react with it as the addition of H2 can take place in the acid having some degree of unsaturation (i.e on multiple bonds).
Since 3rd fatty acid has only 1 degree of unsaturation.
Hence either 1 mole H2 can react with it or none.
Since 2nd fatty acid has 4 degree of unsaturation.
Hence either both H2 moles can react with it or 1 (it can not be zero as there is no other fatty acid with 2 or more degree of unsaturation).
Since in hydrogenation reaction, the number of carbon remains the same.
Hence the number of carbon will remain same in all fatty acids.
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