Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
Which method would you use to determine whether the series /n¹+1 n³+n n=1 converges or diverges? We will use Alternating series procedure, since the terms in this series have (-1)" expression multiplying the ratio We will use limit comparison test and compare this series with the series and therefore the series is convergent! 723 We will use Integral test, since integral of the terms seems fairly easy We will use limit comparison test and compare this series with the series 0 0000 ОО 00 n=1 and therefore the series is convergent! We will use Ratio test, since the terms have ratios and expressions that can easily cancel. We will use Root test, since the n-th root of this expression will simplify the general term, and therefore this series is Absolutely Convergent This series diverges, since the terms don't have limit = 0 We will use limit comparison test and compare this series with the series and therefore the series is divergent! 1 n This series converges, since the terms have limit = 0

Which method would you use to determine whether the series /n¹+1 n³+n n=1 converges or diverges? We will use Alternating series procedure, since the terms in this series have (-1)" expression multiplying the ratio We will use limit comparison test and compare this series with the series and therefore the series is convergent! 723 We will use Integral test, since integral of the terms seems fairly easy We will use limit comparison test and compare this series with the series 0 0000 ОО 00 n=1 and therefore the series is convergent! We will use Ratio test, since the terms have ratios and expressions that can easily cancel. We will use Root test, since the n-th root of this expression will simplify the general term, and therefore this series is Absolutely Convergent This series diverges, since the terms don't have limit = 0 We will use limit comparison test and compare this series with the series and therefore the series is divergent! 1 n This series converges, since the terms have limit = 0

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
See similar textbooks
icon
Related questions
Question
Which method would you use to determine whether the series √nª +1 n³+n Σn=1 converges or diverges? We will use Alternating series procedure, since the terms in this series have (-1)" expression multiplying the ratio We will use limit comparison test and compare this series with the series and therefore the series is convergent! 0 00 00 00 00 We will use Integral test, since integral of the terms seems fairly easy We will use limit comparison test and compare this series with the series 100 1 and therefore the series is convergent! n² We will use Ratio test, since the terms have ratios and expressions that can easily cancel. We will use Root test, since the n-th root of this expression will simplify the general term, and therefore this series is Absolutely Convergent This series diverges, since the terms don't have limit = 0 We will use limit comparison test and compare this series with the series, and therefore the series is divergent! This series converges, since the terms have limit = 0
Transcribed Image Text:Which method would you use to determine whether the series √nª +1 n³+n Σn=1 converges or diverges? We will use Alternating series procedure, since the terms in this series have (-1)" expression multiplying the ratio We will use limit comparison test and compare this series with the series and therefore the series is convergent! 0 00 00 00 00 We will use Integral test, since integral of the terms seems fairly easy We will use limit comparison test and compare this series with the series 100 1 and therefore the series is convergent! n² We will use Ratio test, since the terms have ratios and expressions that can easily cancel. We will use Root test, since the n-th root of this expression will simplify the general term, and therefore this series is Absolutely Convergent This series diverges, since the terms don't have limit = 0 We will use limit comparison test and compare this series with the series, and therefore the series is divergent! This series converges, since the terms have limit = 0
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,
SEE MORE TEXTBOOKS