Which graphical method(s) below would be appropriate for comparing the natural killer cell activity values between the groups? Answer yes or no: A. One histogram with all data pooled across the groups. B. Side-by-side boxplots (one for each group). C. Bar plots. D. Pie Charts. E. Scatterplots. F. Q-Q plots. 2. Fill in the Anova Attchaed in picture. How many groups were being compared? and How many subjects were in each group? 3. A plausible interpretation of the ANOVA table would be: a. None of the above. b. The mean measure of natural killer cell activity is not significantly different between each of the groups. c. The variance between groups is larger than the variance within groups and the mean measure of natural killer cell d. activity is significantly different between each of the groups. e. The variance between groups is larger than the variance within groups. f. The mean measure of natural killer cell activity is significantly different between each of the groups. 4. After the researchers performed the ANOVA, they looked at all of the pairwise comparisons of mean natural killer cell activity levels using the Bonferroni method and an overall significance level of 2%. How many pairwise comparisons did they need to make? What was the significance level for each pairwise test?
Which graphical method(s) below would be appropriate for comparing the natural killer cell activity values between the groups? Answer yes or no: A. One histogram with all data pooled across the groups. B. Side-by-side boxplots (one for each group). C. Bar plots. D. Pie Charts. E. Scatterplots. F. Q-Q plots. 2. Fill in the Anova Attchaed in picture. How many groups were being compared? and How many subjects were in each group? 3. A plausible interpretation of the ANOVA table would be: a. None of the above. b. The mean measure of natural killer cell activity is not significantly different between each of the groups. c. The variance between groups is larger than the variance within groups and the mean measure of natural killer cell d. activity is significantly different between each of the groups. e. The variance between groups is larger than the variance within groups. f. The mean measure of natural killer cell activity is significantly different between each of the groups. 4. After the researchers performed the ANOVA, they looked at all of the pairwise comparisons of mean natural killer cell activity levels using the Bonferroni method and an overall significance level of 2%. How many pairwise comparisons did they need to make? What was the significance level for each pairwise test?
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 2GP
Related questions
Question
100%
Which graphical method(s) below would be appropriate for comparing the natural killer cell activity values between the groups? Answer yes or no:
A. One histogram with all data pooled across the groups.
B. Side-by-side boxplots (one for each group).
C. Bar plots.
D. Pie Charts.
E.
F. Q-Q plots.
2. Fill in the Anova Attchaed in picture. How many groups were being compared? and How many subjects were in each group?
3. A plausible interpretation of the ANOVA table would be:
a. None of the above.
b. The mean measure of natural killer cell activity is not significantly different between each of the groups.
c. The variance between groups is larger than the variance within groups and the mean measure of natural killer cell d. activity is significantly different between each of the groups.
e. The variance between groups is larger than the variance within groups.
f. The mean measure of natural killer cell activity is significantly different between each of the groups.
4. After the researchers performed the ANOVA, they looked at all of the pairwise comparisons of mean natural killer cell activity levels using the Bonferroni method and an overall significance level of 2%.
How many pairwise comparisons did they need to make?
What was the significance level for each pairwise test?
![Fill in the ANOVA table below.
Source
of
Variation
Between
Groups
Within
Groups
Total
Sum of Squares
4653.58
14150.62
Degrees
of
Freedom
2
30
Mean Squares
316.568
F-Statistic
p-
value
<0.001](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2348a137-4566-48a7-9766-25c5c25b6aad%2Fd2ddda82-176f-446f-a395-e31e4a1428bb%2Fo50c0ap_processed.png&w=3840&q=75)
Transcribed Image Text:Fill in the ANOVA table below.
Source
of
Variation
Between
Groups
Within
Groups
Total
Sum of Squares
4653.58
14150.62
Degrees
of
Freedom
2
30
Mean Squares
316.568
F-Statistic
p-
value
<0.001
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