Which formula would be used to calculate the trapezoid approximation of o 3x dx using five subintervals? 0.2 O T5 = [3(0.0)² + (3)(0.2)² + (3)(0.4)² + (3)(0.6)² + (3)(0.8)² + 3(1.0)²] 2 0.2 O T5 = [3(0.0) + 2(3)(0.2) + 2(3)(0.4) + 2(3)(0.6) + 2(3)(0.8) + 3(1.0)] O T5 = 0.4[3(0.0)2+ 2(3)(0.2)² + 2(3)(0.4)² + 2(3)(0.6)² + 2(3)(0.8)2 + 3(1.0)2] T5 = [3(0.0)2 + 2(3)(0.2)? + 2(3)(0.4)² + 2(3)(0.6)? + 2(3)(0.8)² + 3(1.0)ª] 0.2 2
Which formula would be used to calculate the trapezoid approximation of o 3x dx using five subintervals? 0.2 O T5 = [3(0.0)² + (3)(0.2)² + (3)(0.4)² + (3)(0.6)² + (3)(0.8)² + 3(1.0)²] 2 0.2 O T5 = [3(0.0) + 2(3)(0.2) + 2(3)(0.4) + 2(3)(0.6) + 2(3)(0.8) + 3(1.0)] O T5 = 0.4[3(0.0)2+ 2(3)(0.2)² + 2(3)(0.4)² + 2(3)(0.6)² + 2(3)(0.8)2 + 3(1.0)2] T5 = [3(0.0)2 + 2(3)(0.2)? + 2(3)(0.4)² + 2(3)(0.6)? + 2(3)(0.8)² + 3(1.0)ª] 0.2 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Which formula would be used to calculate the trapezoid approximation of 3x- dx using five subintervals?
0.2
(3(0.0)? + (3)(0.2)² + (3)(0.4)² + (3)(0.6)² + (3)(0.8)² + 3(1.0)2]
2
0.2
(3(0.0) + 2(3)(0.2) + 2(3)(0.4) + 2(3)(0.6) + 2(3)(0.8) + 3(1.0)]
O T5
O T5 = 0.4[3(0.0)² + 2(3)(0.2)² + 2(3)(0.4)² + 2(3)(0.6)² + 2(3)(0.8)² + 3(1.0)?]
%3D
0.2
O Ts= 쓱 [3(0.0)2 + 2(3)(0.2)2 + 2(3)(0.4)2 + 2(3)(0.6)2 + 2(3)(0.8)2 + 3(1.0)2]
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6539f692-5656-46fd-b828-f0fe9bb331a2%2F9e956dcc-4ec2-4f0e-ab5f-6e7d2c7ae513%2F8b16goc_processed.png&w=3840&q=75)
Transcribed Image Text:Which formula would be used to calculate the trapezoid approximation of 3x- dx using five subintervals?
0.2
(3(0.0)? + (3)(0.2)² + (3)(0.4)² + (3)(0.6)² + (3)(0.8)² + 3(1.0)2]
2
0.2
(3(0.0) + 2(3)(0.2) + 2(3)(0.4) + 2(3)(0.6) + 2(3)(0.8) + 3(1.0)]
O T5
O T5 = 0.4[3(0.0)² + 2(3)(0.2)² + 2(3)(0.4)² + 2(3)(0.6)² + 2(3)(0.8)² + 3(1.0)?]
%3D
0.2
O Ts= 쓱 [3(0.0)2 + 2(3)(0.2)2 + 2(3)(0.4)2 + 2(3)(0.6)2 + 2(3)(0.8)2 + 3(1.0)2]
2
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