Which ether cannot be prepared via a Williamson ether synthesis? OA di-1-naphthyl ether OR 15-crown-5 Oc butyl phenyl ether OD di-meta-nitrobenzyl ether
Carbohydrates
Carbohydrates are the organic compounds that are obtained in foods and living matters in the shape of sugars, cellulose, and starch. The general formula of carbohydrates is Cn(H2O)2. The ratio of H and O present in carbohydrates is identical to water.
Starch
Starch is a polysaccharide carbohydrate that belongs to the category of polysaccharide carbohydrates.
Mutarotation
The rotation of a particular structure of the chiral compound because of the epimerization is called mutarotation. It is the repercussion of the ring chain tautomerism. In terms of glucose, this can be defined as the modification in the equilibrium of the α- and β- glucose anomers upon its dissolution in the solvent water. This process is usually seen in the chemistry of carbohydrates.
L Sugar
A chemical compound that is represented with a molecular formula C6H12O6 is called L-(-) sugar. At the carbon’s 5th position, the hydroxyl group is placed to the compound’s left and therefore the sugar is represented as L(-)-sugar. It is capable of rotating the polarized light’s plane in the direction anticlockwise. L isomers are one of the 2 isomers formed by the configurational stereochemistry of the carbohydrates.
6.
![QUESTION 42
Which step is NOT an important one in the mechanism of Pd(PPH3)4 catalyzed coupling of 2-iodofuran with
tributylphenyltin?
OA Oxidative addition of Ph-lodofuran by Pd to form the 2-furyl-Pd-I complex.
O Reductive elimination of Ph-Pd-2-furyl complex to form 2-phenylfuran
OC Transmetalation to form Buz3Sn-l and the Ph-Pd-fur-2-yl complex
OD Addition of PPH3 to form the active catalyst
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![QUESTION 40
Which ether cannot be prepared via a Williamson ether synthesis?
OA di-1-naphthyl ether
OR 15-crown-5
Oc butyl phenyl ether
OD di-meta-nitrobenzyl ether
QUESTION 41
utlithlum to give the observed product.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd25fe9de-cc64-4da1-bc6f-50a32221e42f%2Fec50ce7e-3eca-420d-81de-04a4d0d3ab9a%2Fhikhg1n_processed.jpeg&w=3840&q=75)
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