Which equation of a circle has the center, C, and radius, r, as shown in the graph? -3-2 7 T of 7 T -0 C O(x-3)² + (y + 2)² = √26 O(x+3)² + (y-2)² = 26 O(x+3)²+(y-2)² = √26 O(x-3)² + (y + 2)² = 26 26

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Which equation of a circle has the center, C, and radius, r, as shown in the graph?
-3
-2 -1
6
5
4
3
2
1
0
-3
-5
1
2
C
O(x-3)² + (y + 2)² = √26
O(x+3)² + (y-2)² = 26
O(x+3)2 + (y-2)² = √√26
O(x-3)² + (y + 2)² = 26
3
T =
4 5
√26
6
7
8
9
10
Transcribed Image Text:Which equation of a circle has the center, C, and radius, r, as shown in the graph? -3 -2 -1 6 5 4 3 2 1 0 -3 -5 1 2 C O(x-3)² + (y + 2)² = √26 O(x+3)² + (y-2)² = 26 O(x+3)2 + (y-2)² = √√26 O(x-3)² + (y + 2)² = 26 3 T = 4 5 √26 6 7 8 9 10
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