College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:**Question:**
Which equation is correct for wave speed?
**Options:**
1. \( v = f \lambda \)
2. \( v = \frac{1}{T} \lambda \)
3. Both of these
4. Neither of these
It's important to understand the formulas given:
1. \( v = f \lambda \):
- Here, \( v \) represents the wave speed.
- \( f \) stands for the frequency of the wave.
- \( \lambda \) (lambda) is the wavelength.
- This formula correctly represents the relationship between wave speed, frequency, and wavelength for a wave.
2. \( v = \frac{1}{T} \lambda \):
- In this equation, \( v \) also represents the wave speed.
- \( T \) stands for the period of the wave, which is the reciprocal of frequency (\( T = \frac{1}{f} \)).
- \( \lambda \) is the wavelength.
- This formula is another correct way of expressing wave speed, as the relationship holds true because \( \frac{1}{T} \) is indeed the frequency \( f \). Thus, \( \frac{1}{T} \lambda = f \lambda \).
Given this understanding, the correct answer to the question is:
3. **Both of these**
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