Which equation can be used to solve for x in the parallelogram below? Then, solve the equation. (4х-20)° (x+10)° (5х-58)° (2x-28) 5х — 58 — 2х — 28 - 5x – 58 = x +10 5х — 58 + 4х — 20 — 180 5х — 58 + 2х — 28 — 180

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
Which equation can be used to solve for x in
the parallelogram below? Then, solve the
equation.
(4x-20)
(x+10)°
(5х-58)°
(2x-28)ª
5х — 58 — 2х - 28
5х — 58 — х+ 10
-
5х — 58 + 4х — 20 3 180
5x – 58 + 2x – 28 = 180
-
Transcribed Image Text:Which equation can be used to solve for x in the parallelogram below? Then, solve the equation. (4x-20) (x+10)° (5х-58)° (2x-28)ª 5х — 58 — 2х - 28 5х — 58 — х+ 10 - 5х — 58 + 4х — 20 3 180 5x – 58 + 2x – 28 = 180 -
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