**Question:**Which critical value is appropriate for a 99% confidence level where n = 17, σ is unknown, and the population appears to be normally distributed?**Options:**- A. \( z_{\alpha/2} = 2.583 \)- B. \( z_{\alpha/2} = 2.567 \)- C. \( t_{\alpha/2} = 2.921 \)- D. \( t_{\alpha/2} = 2.898 \)*Instruction: Click to select your answer.*

Name: **Question:**Which critical value is appropriate for a 99% confidence
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: **Question:**Which critical value is appropriate for a 99% confidence level where n = 17, σ is unknown, and the population appears to be normally distributed?**Options:**- A. \( z_{\alpha/2} = 2.583 \)- B. \( z_{\alpha/2} = 2.567 \)- C. \( t_{\alpha

The confidence level is 99%, and the sample size is 17. Also standard deviation is unknown and the…

Math

Statistics

Which critical value is appropriate for a 99% confidence level where n= 17, a is unknown, and the population appears to be normally distributed? O A. Za/2=2.583 B. Za/2=2.567 OC ta/2=2.921 O D. a/2=2.898

Which critical value is appropriate for a 99% confidence level where n= 17, a is unknown, and the population appears to be normally distributed? O A. Za/2=2.583 B. Za/2=2.567 OC ta/2=2.921 O D. a/2=2.898

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

H. ANOVA can tell which mean is different. True False I. If a confidence interval for the difference of 2 proportions is found and the interval contains 0, it suggests the proportions are the same. True False
A professor wants to estimate how many hours per week her students study. A simple random sample of 73 students had a mean of 19 hours of studying per week. Construct a 95 % confidence interval for the mean number of hours a student studies per week. Assume that the population standard deviation is known to be 2.9 hours per week. Round to two decimal places,
What is the minimum required sample size to make a 96% confidence interval for a population mean if the margin of error is to be 2 inches and the standard deviation is thought to be about 12 inches?
The length of a certain type of fish is normally distributed with mean and standard deviation sigma = 2.4 inches. The margin of error for a 99% confidence interval is desired to be 0.08 inches. What should be the sample size?
An farmer is convinced that the weighing instrument for palay had a variability measured by standard deviation equal to 2. He recorded the measurements 4.1, 6.5, 5.2 and 10.2. Do these data confirm or disprove his assertion? Use a 95% confidence level.
Suppose the population standard deviation is = 5, an SRS of n = 100 is obtained, and the confidence level is chosen to be 99.5%. The margin of error for estimating a mean is given by: a. 1.576. b. 1.165. c. 1.404. d. 1.223.
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Find a 99% confidence interval on the difference in the mean life. Car Brand 1 Brand 2 1 36,925 34,318 2 45,300 42,280 3 36,256 35.548 4 32,100 31,950 5 37,210 38,015 6 48,360 47,800 7 38.200 37,810 8 33,500 33,215 Round your answer to 2 decimal places. Do not use commas.
Assume that a sample is used to estimate a population mean. Find the 90% confidence interval for a smaple of size 46 with a mean of 68.5 and a standard deviation of 6.6. Enter the answer as an open-interval (parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).
A labor department wants to study mean age of all people in the civilian labor force. The average age of 49 randomly selected people in the civilian labor force is found to be 35.6 years. Assuming the population standard deviation is 11, what is the 95% confidence interval for true population mean?
Work Time Lost due to Accidents At a large company, the Director of Research found that the average work time lost by employees due to accidents was 102 hours per year. She used a random sample of 21 employees. The standard deviation of the sample was 5.4 hours. Estimate the population mean for the number of hours lost due to accidents for the company, using a 99% confidence interval. Assume the variable is normally distributed. Use a graphing calculator and round the answers to the nearest whole number.
Apply the t-interval procedure to find a 95% confidence interval for the mean arterial blood pressure of 8 children sampled if x=85.99 mm Hg and s=8.08 mm Hg
A random sample was selected from a population having a normal distribution. Calculate a 90% confidence interval estimate for for each of the following situations: (a). = 134, n = 10, s = 3.1 (b). = 3,744, n = 120, s = 8.2 (c). = 40.5, n = 9, = 2.9