Which C statement sets bit 7 and bit 4 in the GPIO_PDDR register to 0 and leaves the other bits unchanged. GPIOP_PDDR &= O×FFFFFF5F; GPIO_PDDR = 0XFFFFFF6F; GPIO_PDDR = GPIO_PDDR & 0XFFFFFF6F; GPIO_PDDR = GPIO_PDDR|0x00000090;
Which C statement sets bit 7 and bit 4 in the GPIO_PDDR register to 0 and leaves the other bits unchanged. GPIOP_PDDR &= O×FFFFFF5F; GPIO_PDDR = 0XFFFFFF6F; GPIO_PDDR = GPIO_PDDR & 0XFFFFFF6F; GPIO_PDDR = GPIO_PDDR|0x00000090;
Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Transcribed Image Text:Which C statement sets bit7 and bit 4 in the GPIO_PDDR register to 0 and leaves the other bits unchanged.
GPIOP_PDDR &= 0XFFFFFF5F;
GPIO_PDDR = OXFFFFFF6F;
GPIO_PDDR = GPIO_PDDR & 0XFFFFFF6F;
GPIO_PDDR = GPIO_PDDR|0x00000090;
Expert Solution
Explanation
1) We are required to set bit 7 and bit 4 to 0 others unchanged
2) Bit position 0 to 7 comes in comes in first byte(LSB),
- To set bit postion 7 to 4 to 0 we need to update first byte as 01101111 = 0x6F
- AND(&) Operation can be performed with GPIO_PDDR with last bytes as 6F.
- AND with 1 will not change the value of other parameter bit postion
- AND with 0 will set value of other parameter bit postion to 0
3) For other bytes to remain unchanged with AND operation we can set all bytes as FF.
- So we have FFFFFF6F that needs to AND with GPIO_PDDR
4) So correct option is GPIO_PDDR = GPIO_PDDR&FFFFFF6F
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