Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 23E: If a reaction produces 1.506 kJ of heat, which is trapped in 30.0 g of water initially at 26.5 °C in...
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Question
Can you solve the problems below, there's 2 pages. The page with the number 1 on the top corner is the first page. That page has only two questions located under the picture of the beakers. The other page has a number 4 at the top right corner and that's the 2nd page. On the second page please fill in the blanks and solve the % error. Thank you and please show all your work.
![Sample Calculation:
(4.18J)(50g sol'n)(+10°C) = 2090J(1kJ) = 2.09kJ
(g°C)
(1000J)
5g NacI(1mole NaCI) = .0855 moles
(58.5g NaCI)
AH = 2.09KJI.0855 moles = -24.4/mole
Temp went up, PE down, AH = -
Salt #1 (Na2CO3)
Salt #2 (NH4NO3)
Mass of empty beaker
25.468
Mass of beaker + water
_74.364
76.132
Mass of beaker + water + salt
79.413
81.072
Mass of solution
Mass of salt
Initial temperature
22.55
22.48
°C
final temperature
28.50
15.60
°C
Q of reaction
_kJ
Moles of salt
moles
AHreaction
kJ/mol
Calculate the % error (lit. values: Na2CO3= -28.1kJ/mole; NHẠNO3 = +25.7kJmole
% Error](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ea55b65-6a30-46ce-96b8-2b732a599bb3%2Fa38c3dcc-e7f5-4d08-a4a3-00f4359ca808%2F7c81rsm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sample Calculation:
(4.18J)(50g sol'n)(+10°C) = 2090J(1kJ) = 2.09kJ
(g°C)
(1000J)
5g NacI(1mole NaCI) = .0855 moles
(58.5g NaCI)
AH = 2.09KJI.0855 moles = -24.4/mole
Temp went up, PE down, AH = -
Salt #1 (Na2CO3)
Salt #2 (NH4NO3)
Mass of empty beaker
25.468
Mass of beaker + water
_74.364
76.132
Mass of beaker + water + salt
79.413
81.072
Mass of solution
Mass of salt
Initial temperature
22.55
22.48
°C
final temperature
28.50
15.60
°C
Q of reaction
_kJ
Moles of salt
moles
AHreaction
kJ/mol
Calculate the % error (lit. values: Na2CO3= -28.1kJ/mole; NHẠNO3 = +25.7kJmole
% Error
![A
1.
500
500
30°C 50°C
600 mL
KIMAX
600 mL
KIMAX
50g 10g
NO SAS
Which beaker is hotter?
Which beaker contains more heat?
1 calorie = the heat required to raise 1g of H20 1°C
1g
21°C
1g
15.667°C
=1 calorie
= 1 calorie
20°C
14.667°C
1g
30°C
5g
26°C
= 5 calories
25°C
= 5 calories
25°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ea55b65-6a30-46ce-96b8-2b732a599bb3%2Fa38c3dcc-e7f5-4d08-a4a3-00f4359ca808%2Fzz9cfu8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A
1.
500
500
30°C 50°C
600 mL
KIMAX
600 mL
KIMAX
50g 10g
NO SAS
Which beaker is hotter?
Which beaker contains more heat?
1 calorie = the heat required to raise 1g of H20 1°C
1g
21°C
1g
15.667°C
=1 calorie
= 1 calorie
20°C
14.667°C
1g
30°C
5g
26°C
= 5 calories
25°C
= 5 calories
25°C
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