Can you solve the problems below, there's 2 pages. The page with the number 1 on the top corner is the first page. That page has only two questions located under the picture of the beakers. The other page has a number 4 at the top right corner and that's the 2nd page. On the second page please fill in the blanks and solve the % error. Thank you and please show all your work. Sample Calculation:(4.18J)(50g sol'n)(+10°C) = 2090J(1kJ) = 2.09kJ(g°C)(1000J)5g NacI(1mole NaCI) = .0855 moles(58.5g NaCI)AH = 2.09KJI.0855 moles = -24.4/moleTemp went up, PE down, AH = -Salt #1 (Na2CO3)Salt #2 (NH4NO3)Mass of empty beaker25.468Mass of beaker + water_74.36476.132Mass of beaker + water + salt79.41381.072Mass of solutionMass of saltInitial temperature22.5522.48°Cfinal temperature28.5015.60°CQ of reaction_kJMoles of saltmolesAHreactionkJ/molCalculate the % error (lit. values: Na2CO3= -28.1kJ/mole; NHẠNO3 = +25.7kJmole% Error A1.50050030°C 50°C600 mLKIMAX600 mLKIMAX50g 10gNO SASWhich beaker is hotter?Which beaker contains more heat?1 calorie = the heat required to raise 1g of H20 1°C1g21°C1g15.667°C=1 calorie= 1 calorie20°C14.667°C1g30°C5g26°C= 5 calories25°C= 5 calories25°C

To predict which of the given beaker is hotter.

Answered: Which beaker is hotter? Which beaker…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

Can you solve the problems below, there's 2 pages. The page with the number 1 on the top corner is the first page. That page has only two questions located under the picture of the beakers. The other page has a number 4 at the top right corner and that's the 2nd page. On the second page please fill in the blanks and solve the % error. Thank you and please show all your work.

Sample Calculation:
(4.18J)(50g sol'n)(+10°C) = 2090J(1kJ) = 2.09kJ
(g°C)
(1000J)
5g NacI(1mole NaCI) = .0855 moles
(58.5g NaCI)
AH = 2.09KJI.0855 moles = -24.4/mole
Temp went up, PE down, AH = -
Salt #1 (Na2CO3)
Salt #2 (NH4NO3)
Mass of empty beaker
25.468
Mass of beaker + water
_74.364
76.132
Mass of beaker + water + salt
79.413
81.072
Mass of solution
Mass of salt
Initial temperature
22.55
22.48
°C
final temperature
28.50
15.60
°C
Q of reaction
_kJ
Moles of salt
moles
AHreaction
kJ/mol
Calculate the % error (lit. values: Na2CO3= -28.1kJ/mole; NHẠNO3 = +25.7kJmole
% Error

A
1.
500
500
30°C 50°C
600 mL
KIMAX
600 mL
KIMAX
50g 10g
NO SAS
Which beaker is hotter?
Which beaker contains more heat?
1 calorie = the heat required to raise 1g of H20 1°C
1g
21°C
1g
15.667°C
=1 calorie
= 1 calorie
20°C
14.667°C
1g
30°C
5g
26°C
= 5 calories
25°C
= 5 calories
25°C

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 7 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions