Which arrow-pushing mechanism best explains the bromination of the following alkene shown below?©GMU 2020 Br2 Me OMe C5HgO2Br2 CCI4 O The following mechanism: H (Br Me OMe Br O The following mechanism: Br-Br OMe Me H. O The following mechanism: COME H. Me., Br OMe Br O The following mechanism: H. (Br OMe H. Me Br
Reactions of Ethers
Ethers (R-O-R’) are compounds formed by replacing hydrogen atoms of an alcohol (R-OH compound) or a phenol (C6H5OH) by an aryl/ acyl group (functional group after removing single hydrogen from an aromatic ring). In this section, reaction, preparation and behavior of ethers are discussed in the context of organic chemistry.
Epoxides
Epoxides are a special class of cyclic ethers which are an important functional group in organic chemistry and generate reactive centers due to their unusual high reactivity. Due to their high reactivity, epoxides are considered to be toxic and mutagenic.
Williamson Ether Synthesis
An organic reaction in which an organohalide and a deprotonated alcohol forms ether is known as Williamson ether synthesis. Alexander Williamson developed the Williamson ether synthesis in 1850. The formation of ether in this synthesis is an SN2 reaction.
![### Exploring Bromination Mechanisms of Alkenes
**Question:**
Which arrow-pushing mechanism best explains the bromination of the following alkene shown below?
- **Reaction:**
\[ \text{MeO}C=C(\text{Me})C=O\]
- Reagent: \( \text{Br}_2 \)
- Solvent: \( \text{CCl}_4 \)
- Product: \( \text{C}_5\text{H}_8\text{O}_2\text{Br}_2 \)
**Options:**
1. **Mechanism 1:**
- The double bond attacks a bromine (Br) in \( \text{Br}_2 \), forming a bromonium ion. The bromide ion then attacks a carbon, opening the bromonium ion.
2. **Mechanism 2:**
- The bromine molecule adds across the double bond without forming a bromonium ion, showing a concerted mechanism.
3. **Mechanism 3:**
- An initial lone pair on an oxygen atom forms a double bond, pushing electrons through the molecule and attacking \( \text{Br}_2 \), forming a cyclic structure involving bromine.
4. **Mechanism 4:**
- The double bond forms a bromonium ion with one bromine, followed by the attack of the bromide ion on one of the carbons of the ion, opening the bromonium.
Each mechanism involves intricate electron movements where bromine interacts with the double bond in the alkene, highlighting the importance of understanding arrow-pushing in chemical reactions.
The correct answer will demonstrate the typical mechanism of electrophilic addition, illustrating how the double bond of the alkene interacts with bromine in a solvent like carbon tetrachloride (CCl₄).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F690e4418-7127-49de-98c7-878039be3670%2F026ee354-868c-4066-8b22-5620a6795c6c%2Frg9wwgn_processed.jpeg&w=3840&q=75)

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