Solve the equation y' - y = f(t), y(0) = 0 t/2 F(t) = (1/² 3 where f(t)= a. b. C. d. y(t) = y(t) = y(t) = y(t) = 9>150 t>6 F(s) = 1 [1-6-6²] ܐܨ [cost+t-µ(t-6)(t - 6 - cos(t – 6))]) [sint+t-μ(t-6)(t− 6 – sin(t — 6))] [sint +t− µ(t− 6)(t – sin(t))] [sint + 1 - µ(t-6)(t− 6 – sin(t – 6))]

Q: 1 Y(s) 4 5s2 S

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Q: 6. Find f '(x) for f(x) = %3D 6. f '(x) =

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