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Where does the 21.8 x 10-19 come from in the problem below? is there any easier way to calculate?      The energy required when an electron jump from  n = 3 to n=7 is calculated as follows: ∆E=E3−E7        =21.8×10−19(132−172)       =21.8×10−19(49−99×49)       =1.97×10−19 J∆E=E3-E7        =21.8×10-19132-172       =21.8×10-1949-99×49       =1.97×10-19 J Thus, the energy needed to promote an electron from n = 3 to n=7 is 1.97 x 10-19

Where does the 21.8 x 10-19 come from in the problem below? is there any easier way to calculate?      The energy required when an electron jump from  n = 3 to n=7 is calculated as follows: ∆E=E3−E7        =21.8×10−19(132−172)       =21.8×10−19(49−99×49)       =1.97×10−19 J∆E=E3-E7        =21.8×10-19132-172       =21.8×10-1949-99×49       =1.97×10-19 J Thus, the energy needed to promote an electron from n = 3 to n=7 is 1.97 x 10-19

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Where does the 21.8 x 10-19 come from in the problem below? is there any easier way to calculate? 

 

 

The energy required when an electron jump from  n = 3 to n=7 is calculated as follows:

∆E=E3−E7     

  =21.8×10−19(132−172)    

  =21.8×10−19(49−99×49)     

 =1.97×10−19 J∆E=E3-E7      

 =21.8×10-19132-172    

  =21.8×10-1949-99×49      

=1.97×10-19 J

Thus, the energy needed to promote an electron from n = 3 to n=7 is 1.97 x 10-19 J.

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