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Where does 179.8 Fe(NO3)2 came from?

Where does 179.8 Fe(NO3)2 came from?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Where does 179.8 Fe(NO3)2 came from? 

Moles of sodium phosphate= 1 mol Na3PO4 = 164.0 g Na3PO4 0.24 g NaзPO4х 0.0015 mol The moles of sodium phosphate is 0. 0015 mol. The moles of iron (ii) nitrate is calculated as, Moles of iron (ii) nitrate= 3 mol Fe(NO3)2 0.0015 тol NazРО4 X = 0.002 2 mol Na3PO4 The moles of iron (ii) nitrate is 0. 0022 mol Fe(NO3)2. The grams of iron (ii) nitrate is calculated as, Grams of iron (ii) nitrate= 0.0022 mol Fe(NO3)2 × 179.8 Fe(NO3)2 1 mol Fe(NO3)2 = 0. 40 g The grams of iron (ii) nitrate is 0. 40 g. 0.40g of iron (ii) nitrate will react with 0.24g sodium phosphate.
Transcribed Image Text:Moles of sodium phosphate= 1 mol Na3PO4 = 164.0 g Na3PO4 0.24 g NaзPO4х 0.0015 mol The moles of sodium phosphate is 0. 0015 mol. The moles of iron (ii) nitrate is calculated as, Moles of iron (ii) nitrate= 3 mol Fe(NO3)2 0.0015 тol NazРО4 X = 0.002 2 mol Na3PO4 The moles of iron (ii) nitrate is 0. 0022 mol Fe(NO3)2. The grams of iron (ii) nitrate is calculated as, Grams of iron (ii) nitrate= 0.0022 mol Fe(NO3)2 × 179.8 Fe(NO3)2 1 mol Fe(NO3)2 = 0. 40 g The grams of iron (ii) nitrate is 0. 40 g. 0.40g of iron (ii) nitrate will react with 0.24g sodium phosphate.
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