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Where did they get 10log (G) from

Where did they get 10log (G) from

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Where did they get 10log (G) from?
Exercise 17. A pulse radar operating at 10 GHz has an antenna with a gain of 28 dB, and a transmitter power of 2 kW (peak power). If it is desired to detect a target with a cross section of 12 m², and the minimum detectable signal is Pmin=-90 dBm, what is the maximum range of the radar? Ans: 8114 m.
Transcribed Image Text:Exercise 17. A pulse radar operating at 10 GHz has an antenna with a gain of 28 dB, and a transmitter power of 2 kW (peak power). If it is desired to detect a target with a cross section of 12 m², and the minimum detectable signal is Pmin=-90 dBm, what is the maximum range of the radar? Ans: 8114 m.
Step1 a) A = Blog₁0 (C) 。 (c) = log10 A C = 10 B Step2 b) So in the above problem G and Pmin give id dB and when you convert to decimal value so we need to follow this step GdB = 10 log10 (G) 28 10 G = 102.8 631 = log10 (G) = (Pmin)dB = 10 log10(Pmin) –90 = 10 logıo(Pmin) 10 Pmin Pmin Step3 c) C = 10 -90 10 10 mW 10-¹² W
Transcribed Image Text:Step1 a) A = Blog₁0 (C) 。 (c) = log10 A C = 10 B Step2 b) So in the above problem G and Pmin give id dB and when you convert to decimal value so we need to follow this step GdB = 10 log10 (G) 28 10 G = 102.8 631 = log10 (G) = (Pmin)dB = 10 log10(Pmin) –90 = 10 logıo(Pmin) 10 Pmin Pmin Step3 c) C = 10 -90 10 10 mW 10-¹² W
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