When X has a binomial distribution with total number n of trials and success probability p, we use the notation, X\sim B(n,p). Suppose that independent random variables X and Y have binomial distributions such that X\sim B(n,p) and Y\sim B(n,q), where 0 The mgf X+Y of 2(pe^t + (1-p))^{n} is when p=q. E[X+Y] = 2n when p+q=1 (n-X) \sim B(n,1-p)
When X has a binomial distribution with total number n of trials and success probability p, we use the notation, X\sim B(n,p). Suppose that independent random variables X and Y have binomial distributions such that X\sim B(n,p) and Y\sim B(n,q), where 0 The mgf X+Y of 2(pe^t + (1-p))^{n} is when p=q. E[X+Y] = 2n when p+q=1 (n-X) \sim B(n,1-p)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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When X has a binomial distribution with total number n of trials and success probability p, we use the notation, X\sim B(n,p).
Suppose that independent random variables X and Y have binomial distributions such that X\sim B(n,p) and Y\sim B(n,q), where 0<p<1 and 0<q<1.
Answer the following true/false questions.
(n-X+Y) \sim B(2n,q) when p+q=1 <True or False>
The mgf X+Y of 2(pe^t + (1-p))^{n} is when p=q. <True or False>
E[X+Y] = 2n when p+q=1 <True or False>
(n-X) \sim B(n,1-p) <True or False>
X(1-Y) \sim B(1,p(1-q)) when n=1 <True or False>
P(X=x,Y=y) = P(XY = xy) <True or False>
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