When using Laplace transform to solve the IVP :Xn = 'n u(x,0)= - x. t>0 Then u]= 1 - SX e a. SX ce Sx s2 b. 1 s2 1 -SX+ - Sx S O d. 1 - SX - --e SX e. S 1 SX s- O f. e SX -- O g. - SX + e - SX -ce e O h.
When using Laplace transform to solve the IVP :Xn = 'n u(x,0)= - x. t>0 Then u]= 1 - SX e a. SX ce Sx s2 b. 1 s2 1 -SX+ - Sx S O d. 1 - SX - --e SX e. S 1 SX s- O f. e SX -- O g. - SX + e - SX -ce e O h.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![When using Laplace transform to solve the IVP
-8
<x<0∞,
t>0
u(x,0)= - x.
f
Then u]=
O a.
- SX -
e Sx -ce Sx
- -
SX.
O b.
1
c.
1
e
-SX
d.
- SX
1
SX
1
e SX
1
e SX
1
- SX+
e
Sx - c ex
g.
e
O h. x
s2
S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5bc6804f-4ced-4f3f-a1c2-d74fc99669be%2Fa91cda73-056d-4902-8e0c-ca79aad3a2cd%2Fgcf35q8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When using Laplace transform to solve the IVP
-8
<x<0∞,
t>0
u(x,0)= - x.
f
Then u]=
O a.
- SX -
e Sx -ce Sx
- -
SX.
O b.
1
c.
1
e
-SX
d.
- SX
1
SX
1
e SX
1
e SX
1
- SX+
e
Sx - c ex
g.
e
O h. x
s2
S
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