When using integration by parts to evaluate the integral fx²e-²x dx and du pick u = that du = and v= which means

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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When using integration by parts to evaluate the integral

\[
\int x^2 e^{-2x} \, dx
\]

pick \( u = \) [blank box] and \( dv = \) [blank box], which means that \( du = \) [blank box] and \( v = \) [blank box].
Transcribed Image Text:When using integration by parts to evaluate the integral \[ \int x^2 e^{-2x} \, dx \] pick \( u = \) [blank box] and \( dv = \) [blank box], which means that \( du = \) [blank box] and \( v = \) [blank box].
Expert Solution
Step 1

Concept:

To combine the end result of two or more functions, integration by parts is utilized. The two functions to be integrated are of the form f(x) and g(x) . As a result, it qualifies as a product integration rule. The first function, f(x), is chosen from the two functions in such a way that its derivative formula exists, while the second function, g(x), is chosen in such a way that its integral formula exists.

f(x)g(x)=f(x)g(x)dx-ddxf(x)g(x)dxdx+C

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