When using divided differences to compute Hermite splines, we defined a divided difference with two identical arguments f[x,, z] as the limit: f(x,x] lim fx₁,x] and used this definition to show that f[x₁₁x₁] = f'(x₁) = y₁₁ (a) Let a divided difference f[x,,,,,] be defined as the limit: f[x₁, x, xi]:=lim f[xi — €, x₁, xi + e] Show that f[a,,a,,a]=f"(x) = . You may use (without proof) the following limit: f(x-e)-2f(x) + f(x+e) f"(x) (b) Explain how Newton interpolation and divided differences can be used to compute a cubic polynomial s(ar) over [zo, z1] such that lim €0 s(xo) s'(zo) s" (xo) s(x₁) Yo % Yo 9/1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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8. When using divided differences to compute Hermite splines, we defined a
divided difference with two identical arguments f[x₁, ₁] as the limit:
f[₁,₁]=lim f[*₁,*]
and used this definition to show that f[x₁, x] = f'(x₁) = -
(a) Let a divided difference f[i, ₁, ₁] be defined as the limit:
f[ri, Ti, Ti] := lim f[xi — €, Xi, Xi + €]
==
Show that f[₁,₁, ] = f'(x) =
You may use (without proof) the following limit:
lim
0+
f(x − €) -2f(x) + f(x + c)
(b) Explain how Newton interpolation and divided differences can be
used to compute a cubic polynomial s(r) over [0, 1] such that
s(To)
s' (TO)
s" (zo)
s(x1)
= f'(x)
Yo
%
30
Y1
Transcribed Image Text:8. When using divided differences to compute Hermite splines, we defined a divided difference with two identical arguments f[x₁, ₁] as the limit: f[₁,₁]=lim f[*₁,*] and used this definition to show that f[x₁, x] = f'(x₁) = - (a) Let a divided difference f[i, ₁, ₁] be defined as the limit: f[ri, Ti, Ti] := lim f[xi — €, Xi, Xi + €] == Show that f[₁,₁, ] = f'(x) = You may use (without proof) the following limit: lim 0+ f(x − €) -2f(x) + f(x + c) (b) Explain how Newton interpolation and divided differences can be used to compute a cubic polynomial s(r) over [0, 1] such that s(To) s' (TO) s" (zo) s(x1) = f'(x) Yo % 30 Y1
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