When the Laplace Transform is applied to the initial value problem y"-2y + y =t + 2e" sin t cost , y(0) = y' (0) = 0- where the Laplace Transform of the solution function y(t) is L{y(t)} = Y(s). Which of the following expression is obtained? Y(s) =- (s+1) (s- 2)² +4 2(s+2) Y(s) = (s-1) (s+2)² +4 2 Y(s)=- (s-1) (s+2)° +4 1 Y(s) = (s-1) (s-1) (s+2) +4 1 Y(s) = 2 (s+1)? (s– 2)² +4

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