**Organic Chemistry Reaction: Racemization of Optically Active Alcohol**When the following optically active alcohol is treated with HBr, a racemic mixture of alkyl bromides is obtained:**Chemical Reaction:**- Reactant: An optically active alcohol.- Reagent: HBr.- Products: A racemic mixture of brominated alkyl chains and water ($ H_2O $).**Diagram Explanation:**The diagram illustrates a chemical reaction where an optically active alcohol undergoes treatment with hydrobromic acid (HBr) to form a racemic mixture. The alcohol loses its hydroxyl group (OH), replaced by a bromine atom (Br), resulting in the formation of a racemic mixture showing two enantiomers of the brominated product.**Task:**Draw the mechanism for this process and explain the stereochemical outcome.This process involves the generation of a carbocation intermediate, which leads to the formation of a racemic mixture due to the equal probability of bromine attacking from either side of the planar carbocation. Add curved arrow(s) to draw step 2 of the mechanism. Modify the given drawing of the product as needed, and show both products.**Diagram Explanation:**The diagram shows a reaction mechanism step involving a structural transformation. On the left side, there is a chemical structure with a protonated oxygen (O⁺) highlighted in red, indicating a positive charge. It is part of an ether group attached to a chain of carbon atoms.The right side shows the product of the mechanism, where the orientation of the atoms around the oxygen has changed. The protonated oxygen (O⁺) remains highlighted in red, and the surrounding carbon atoms are adjusted in their spatial arrangement.An arrow indicates the direction of the reaction, showing the conversion from the starting structure to the product structure.Below the diagram, there is a button labeled "Edit Drawing."

The mechanism is provided in the next step:

When the following optically active alcohol is treated with HBr, a racemic mixture of alkyl bromides is obtained: Br HBr + H20 Racemic mixture Draw the mechanism for this process, and explain the stereochemical outcome.

When the following optically active alcohol is treated with HBr, a racemic mixture of alkyl bromides is obtained: Br HBr + H20 Racemic mixture Draw the mechanism for this process, and explain the stereochemical outcome.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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