For the reaction 2CO(g) + O₂(g) = 2CO₂(g), the value of K at a certain temperature is 1310. Part A Calculate [0₂] at equilibrium when [CO₂] = 0.18 mol/L and [CO] =2.01x10-² mol/L. Express your answer using two significant figures. ΨΕΙ ΑΣΦΑ [0₂] = Submit Part B * Incorrect; Try Again; 9 attempts remaining (CO₂) = Previous Answers Request Answer Submit Provide Feedback DA Calculate [CO₂] at equilibrium when [CO] = 8.1x10-2 mol/L and [0₂] = 0.521 mol/L Express your answer using two significant figures. 15. ΑΣΦ Request Answer ? mol/L ? mol/L

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**Collision Theory and Equilibrium: Problem 7.59**

**Problem Statement:**

For the reaction:
\[ 2\text{CO}(g) + \text{O}_2(g) \rightarrow 2\text{CO}_2(g) \]

The equilibrium constant \( K \) at a certain temperature is 1310.

---

**Part A:**

Calculate \([\text{O}_2]\) at equilibrium when \([\text{CO}_2] = 0.18 \, \text{mol/L}\) and \([\text{CO}] = 2.01 \times 10^{-2} \, \text{mol/L}\).

- Express your answer using two significant figures.

Input box for \([\text{O}_2]\) in \(\text{mol/L}\).

*Response: Incorrect; Try Again; 9 attempts remaining.*

---

**Part B:**

Calculate \([\text{CO}_2]\) at equilibrium when \([\text{CO}] = 8.1 \times 10^{-2} \, \text{mol/L}\) and \([\text{O}_2] = 0.521 \, \text{mol/L}\).

- Express your answer using two significant figures.

Input box for \([\text{CO}_2]\) in \(\text{mol/L}\).

Buttons for submitting, previous answers, and request answer.

---

Students are asked to use the provided equilibrium constant and concentration data to solve for the unknown concentrations in a chemical reaction at equilibrium. This exercise involves applying the equilibrium constant expression:

\[ K = \frac{[\text{CO}_2]^2}{[\text{CO}]^2 [\text{O}_2]} \]

**Note**: Ensure your calculations adhere to the rules for significant figures as specified.
Transcribed Image Text:**Collision Theory and Equilibrium: Problem 7.59** **Problem Statement:** For the reaction: \[ 2\text{CO}(g) + \text{O}_2(g) \rightarrow 2\text{CO}_2(g) \] The equilibrium constant \( K \) at a certain temperature is 1310. --- **Part A:** Calculate \([\text{O}_2]\) at equilibrium when \([\text{CO}_2] = 0.18 \, \text{mol/L}\) and \([\text{CO}] = 2.01 \times 10^{-2} \, \text{mol/L}\). - Express your answer using two significant figures. Input box for \([\text{O}_2]\) in \(\text{mol/L}\). *Response: Incorrect; Try Again; 9 attempts remaining.* --- **Part B:** Calculate \([\text{CO}_2]\) at equilibrium when \([\text{CO}] = 8.1 \times 10^{-2} \, \text{mol/L}\) and \([\text{O}_2] = 0.521 \, \text{mol/L}\). - Express your answer using two significant figures. Input box for \([\text{CO}_2]\) in \(\text{mol/L}\). Buttons for submitting, previous answers, and request answer. --- Students are asked to use the provided equilibrium constant and concentration data to solve for the unknown concentrations in a chemical reaction at equilibrium. This exercise involves applying the equilibrium constant expression: \[ K = \frac{[\text{CO}_2]^2}{[\text{CO}]^2 [\text{O}_2]} \] **Note**: Ensure your calculations adhere to the rules for significant figures as specified.
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