When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the total mechanical energy is kinetic energy? A. 1/16 В. 1/2 C. 1/4 D. 3/4

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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### Question 4

**Points:** 0 / 1 

When the displacement of a mass on a spring in simple harmonic motion is \( A/2 \) from the equilibrium position, what fraction of the total mechanical energy is kinetic energy?

- A. \( \frac{1}{16} \)
- B. \( \frac{1}{2} \)
- C. \( \frac{1}{4} \)
- D. \( \frac{3}{4} \)

*Selected Answer:* C

---

### Question 5

**Status:** Incorrect 

**Points:** 0 / 1 

We can relate the simple harmonic motion of a mass-spring system to uniform circular motion by projecting the shadow of a particle on the edge of a rotating wheel onto a screen. If the position angle of the particle at \( 0^\circ \) corresponds to \( x = +A \) for the mass-spring system, which angle corresponds to \( x = +A/2 \)? (Referring to the figure in the second lecture video may help.)

- A. \( 60^\circ \)
- B. \( 90^\circ \)
- C. \( 45^\circ \)
- D. \( 180^\circ \)
Transcribed Image Text:### Question 4 **Points:** 0 / 1 When the displacement of a mass on a spring in simple harmonic motion is \( A/2 \) from the equilibrium position, what fraction of the total mechanical energy is kinetic energy? - A. \( \frac{1}{16} \) - B. \( \frac{1}{2} \) - C. \( \frac{1}{4} \) - D. \( \frac{3}{4} \) *Selected Answer:* C --- ### Question 5 **Status:** Incorrect **Points:** 0 / 1 We can relate the simple harmonic motion of a mass-spring system to uniform circular motion by projecting the shadow of a particle on the edge of a rotating wheel onto a screen. If the position angle of the particle at \( 0^\circ \) corresponds to \( x = +A \) for the mass-spring system, which angle corresponds to \( x = +A/2 \)? (Referring to the figure in the second lecture video may help.) - A. \( 60^\circ \) - B. \( 90^\circ \) - C. \( 45^\circ \) - D. \( 180^\circ \)
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