When solving for t below, one step contains an error. log log1.12 log should be V = 8,000 (1.12) t V (1.12) 8,000 V 8,000 log should be Which step(s) contain the error(s) and what is the correct solution method? log V 8,000 V 8,000 V 8,000 V 1.12 = t -log(1.12) = t log V 1.12 log(8,000) - log(1.12) = t = t - log(1.12) = t - log(8, 000) = t
When solving for t below, one step contains an error. log log1.12 log should be V = 8,000 (1.12) t V (1.12) 8,000 V 8,000 log should be Which step(s) contain the error(s) and what is the correct solution method? log V 8,000 V 8,000 V 8,000 V 1.12 = t -log(1.12) = t log V 1.12 log(8,000) - log(1.12) = t = t - log(1.12) = t - log(8, 000) = t
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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log
should be
should be
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V
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log
8,000
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log 8,000
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Transcribed Image Text:should be
log
should be
should be
should be
V
8,000
V
1.12
V
8,000
log1.12
log
log
8,000
log(1.12)
= (1.12)
log1.12
(8,000)
log 8,000
- log(1.12) =
V
8,000
V
8,000
1.12
V
8,000
= t
1.12
= t
= t
= t
- = t
= t

Transcribed Image Text:When solving for t below, one step contains
an error.
log
log1.12
log
should be
V = 8,000 (1.12)
V
8,000
V
8,000
log
should be
— log(1.12) = t
Which step(s) contain the error(s) and what is
the correct solution method?
log
V
8,000
=
(1.12)
V
8,000
V
8,000
V
1.12
V
log 1.12
log (8,000)
= t
- log(1.12) = t
= t
— log(1.12) = t
- log(8, 000) = t
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