When rebuilding his car's engine, a physics major must continuously exert 4.02 ✕ 102 N of force to insert a dry steel piston as it slides into a steel cylinder. What is the normal force (in N) between the piston and cylinder? (Enter the magnitude.)

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When rebuilding his car's engine, a physics major must continuously exert 4.02 ✕ 102 N of force to insert a dry steel piston as it slides into a steel cylinder. What is the normal force (in N) between the piston and cylinder? (Enter the magnitude.)

(a) When rebuilding his car's engine, a physics major must continuously exert 4.02 × 102 N of force to insert a dry steel piston as it slides into a steel cylinder. What is the normal force (in N) between the piston
and cylinder? (Enter the magnitude.)
0.3
X N
(b) What force (in N) would he have to continuously exert if the steel parts were oiled? (Enter the magnitude.)
40.2
N
Transcribed Image Text:(a) When rebuilding his car's engine, a physics major must continuously exert 4.02 × 102 N of force to insert a dry steel piston as it slides into a steel cylinder. What is the normal force (in N) between the piston and cylinder? (Enter the magnitude.) 0.3 X N (b) What force (in N) would he have to continuously exert if the steel parts were oiled? (Enter the magnitude.) 40.2 N
Expert Solution
Step 1

Given Data:

The force applied is, F=4.02×102 N

 

The expression for the normal reaction force is,

F=μNN=Fμ............(1)

Here, F is the applied force and μ is the coefficient of static friction for dry steel μ=0.6.

 

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