When light with a wavelength of 208 nm is incident on a certain metal surface, electrons are ejected with a maximum kinetic energy of 2.47 × 10-19 J. Determine the wavelength (in nm) of light that should be used to double the maximum kinetic energy of the electrons ejected from this surface. Number i Units
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The answers I got were 2.08e-7, and 2.74e-19
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