When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3 (s)+CaO(s) + CO₂(g) What is the mass of calcium carbonate needed to produce 55.0 L of carbon dioxide at STP? Express your answer with the appropriate units. View Available Hint(s) mass of CaCO3= Submit Part B HA Value Units Butane, C, H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is 2C Ho (9)+1302 (9) 8CO₂ (9)+10H₂O(l) At 1.00 atm and 23 °C, what is the volume of carbon dioxide formed by the combustion of 1.60 g of butane? Express your answer with the appropriate units. View Available Hint(s)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answer part a and b
**Educational Content Transcription:**

---

**The Ideal Gas Law**

The ideal gas law is represented as:

\[ PV = nRT \]

- **P** represents pressure
- **V** represents volume
- **T** represents temperature
- **n** represents the number of moles of a gas
- **R** is the gas constant, with a value of 0.08206 L·atm/(K·mol) or 8.3145 J/(K·mol)

The equation can be rearranged to solve for moles:

\[ n = \frac{PV}{RT} \]

This equation is useful when dealing with gaseous reactions because stoichiometric calculations often involve mole ratios.

---

**Part A**

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction:

\[ \text{CaCO}_3(s) \rightarrow \text{CaO}(s) + \text{CO}_2(g) \]

**Problem:** What is the mass of calcium carbonate needed to produce 55.0 L of carbon dioxide at STP (Standard Temperature and Pressure)?

**Solution:** Express your answer with the appropriate units.

- Mass of CaCO₃ = [Input Field for Value] [Input Field for Units]

**Submit Button**

---

**Part B**

Butane, \( \text{C}_4\text{H}_{10} \), is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is:

\[ 2\text{C}_4\text{H}_{10}(g) + 13\text{O}_2(g) \rightarrow 8\text{CO}_2(g) + 10\text{H}_2\text{O}(l) \]

**Problem:** At 1.10 atm and 23°C, what is the volume of carbon dioxide formed by the combustion of 1.60 g of butane? 

**Solution:** Express your answer with the appropriate units.

- Volume of CO₂ = [Input Field for Value] [Input Field for Units]

**Submit Button**

---
Transcribed Image Text:**Educational Content Transcription:** --- **The Ideal Gas Law** The ideal gas law is represented as: \[ PV = nRT \] - **P** represents pressure - **V** represents volume - **T** represents temperature - **n** represents the number of moles of a gas - **R** is the gas constant, with a value of 0.08206 L·atm/(K·mol) or 8.3145 J/(K·mol) The equation can be rearranged to solve for moles: \[ n = \frac{PV}{RT} \] This equation is useful when dealing with gaseous reactions because stoichiometric calculations often involve mole ratios. --- **Part A** When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction: \[ \text{CaCO}_3(s) \rightarrow \text{CaO}(s) + \text{CO}_2(g) \] **Problem:** What is the mass of calcium carbonate needed to produce 55.0 L of carbon dioxide at STP (Standard Temperature and Pressure)? **Solution:** Express your answer with the appropriate units. - Mass of CaCO₃ = [Input Field for Value] [Input Field for Units] **Submit Button** --- **Part B** Butane, \( \text{C}_4\text{H}_{10} \), is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is: \[ 2\text{C}_4\text{H}_{10}(g) + 13\text{O}_2(g) \rightarrow 8\text{CO}_2(g) + 10\text{H}_2\text{O}(l) \] **Problem:** At 1.10 atm and 23°C, what is the volume of carbon dioxide formed by the combustion of 1.60 g of butane? **Solution:** Express your answer with the appropriate units. - Volume of CO₂ = [Input Field for Value] [Input Field for Units] **Submit Button** ---
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