CAN SOMONE EXPLAIN THIS TO ME? When going through a section, try the Self-check exercises. The solutions are given at the end of each chapter.1. Determine the output from the following program:public static void main (String[] zzz) {int result = comp (4, 2);out.println ("Result} // end mainOutputcomp ( 4, 2) calledcomp (3, 2) calledcomp (2, 2) calledcomp (2, 1) called" + result);%3Dcomp (1, 1) calledcomp (1, 0) calledcomp (3, 1) calledcomp (2, 1) calledcomp (1, 1) calledstatic int comp (int n, int k) {out.println ("comp (" + n + ", " + k + ") called");if ( (n ==k) || (k == 0) )return 1;int a = comp (nint b = comp (nreturn a + b;} // end compThe tree diagram of recursive calls1, k);comp (1, 0) calledcomp (2, 0) called1, k1);Resultcomp(4, 2)↑6comp(3, 2)↑3comp(3, 1)↑3comp(2, 2)↑1comp(2, 1)↑2comp(2, 1)↑2comp(2, 0)↑1comp(1, 1)↑1 comp(1, 0)↑1 comp(1, 1)↑1 comp(1, 0)↑1

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When going through a section, try the Self-check exercises. The solutions are given at the end of each chapter. 1. Determine the output from the following program: public static void main (String[] zzz) { int result = comp(4, 2); out.println ("Result = " + result); } // end main Output comp (4, 2) called comp (3, 2) called comp (2, 2) called comp (2, 1) called comp (1, 1) called comp (1, 0) called comp (3, 1) called comp (2, 1) called comp (1, 1) called comp (1, 0) called comp (2, 0) called Result = 6 static int comp(int n, int k) { out.println("comp(" + n + ", " + k + ") called"); if ( (n == k) || (k 0) ) == return 1; int a = comp (n int b = comp (n - 1, k - 1); return a + b; } // end comp 1, k); The tree diagram of recursive calls comp(4, 2)↑6 comp(3, 2)↑3 comp(3, 1)↑3 comp(2, 2)↑1 comp(2, 1)↑2 comp(2, 1)↑2 comp(2, 0)↑1 comp(1, 1)↑1 comp(1, 0)↑1 comp(1, 1)↑1 comp(1, 0)↑1