When finding an inverse by hand, the original matrix is written in augmented form. 1 -1 1 1 -1|0 1 6 -2 -30 0 1 The goal is to get the left side to be the identity matrix, which yields the inverse on the right. About halfway through this process of finding Reduced Row Echelon Form, this matrix is achieved where the leading coefficient of each row is either a 0 or a 1. Start with the augmented matrix above and then follow the mathematical instructions below: R2 = R2 – RỊ R3 = R3 – 6R1 R3 = R3 – 4R2 1 b| d f] a e This results in: 0 1 c|g h j 0 0 1| k m Which of the following would be the correct solution after these 3 steps have been applied? 1 -1 2 1 6. 1 -1 -1 -2 -1 1 1 -1 1 1 -1 -1 1 -2 -4 1 1 1 -3 1 3 2 -4 0 0 1-1 -1 1 -3 2 -2 -3 1 -6-3 -3 1 -2 -4 1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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When finding an inverse by hand, the original matrix is written in augmented form.
1
-1
1
1
-1|0
1
6 -2
-30 0
1
The goal is to get the left side to be the identity matrix, which yields the inverse on the right.
About halfway through this process of finding Reduced Row Echelon Form, this matrix is achieved
where the leading coefficient of each row is either a 0 or a 1.
Start with the augmented matrix above and then follow the mathematical instructions below:
R2 = R2 – RỊ
R3 = R3 – 6R1
R3 = R3 – 4R2
1
b| d
f]
a
e
This results in:0
1
c| g
h
j
0 0
1| k
m
Which of the following would be the correct solution after these 3 steps have been applied?
1
-1
2
1
1
-1
-1
1
-2
-1
1
1
-1
1
1
-1
-1
-2
-4
1
1
1
-3
1
3
2
-4
0 0
1-1
-1
1
-3
2
-2
-3
1
-6|-3
-3
1
-2
-4
Transcribed Image Text:When finding an inverse by hand, the original matrix is written in augmented form. 1 -1 1 1 -1|0 1 6 -2 -30 0 1 The goal is to get the left side to be the identity matrix, which yields the inverse on the right. About halfway through this process of finding Reduced Row Echelon Form, this matrix is achieved where the leading coefficient of each row is either a 0 or a 1. Start with the augmented matrix above and then follow the mathematical instructions below: R2 = R2 – RỊ R3 = R3 – 6R1 R3 = R3 – 4R2 1 b| d f] a e This results in:0 1 c| g h j 0 0 1| k m Which of the following would be the correct solution after these 3 steps have been applied? 1 -1 2 1 1 -1 -1 1 -2 -1 1 1 -1 1 1 -1 -1 -2 -4 1 1 1 -3 1 3 2 -4 0 0 1-1 -1 1 -3 2 -2 -3 1 -6|-3 -3 1 -2 -4
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