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When excess solid YZ is put in water and allowed to dissolve the following equilibrium reaction occurs and the equilibrium table shown can be set up. YZ(s) excess [initial] [change] -x [equilibrium] excess - x =Y+ (aq) + Z¯(aq) 0 0 +x +x +x +x The amount of solid that dissolves is called the molar solubility, denoted here by x. Since the concentration of the solid is constant and is not included in the Ksp expression, the equilibrium expression for the reaction is Ksp = [Y][Z], or, in terms of molar solubility, Ksp = x². Enter the Ksp expression for the solid AB₂ in terms of the molar solubility . Express your answer in terms of x. ► View Available Hint(s) Ksp = Submit 17 ΑΣΦ ?

When excess solid YZ is put in water and allowed to dissolve the following equilibrium reaction occurs and the equilibrium table shown can be set up. YZ(s) excess [initial] [change] -x [equilibrium] excess - x =Y+ (aq) + Z¯(aq) 0 0 +x +x +x +x The amount of solid that dissolves is called the molar solubility, denoted here by x. Since the concentration of the solid is constant and is not included in the Ksp expression, the equilibrium expression for the reaction is Ksp = [Y][Z], or, in terms of molar solubility, Ksp = x². Enter the Ksp expression for the solid AB₂ in terms of the molar solubility . Express your answer in terms of x. ► View Available Hint(s) Ksp = Submit 17 ΑΣΦ ?

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.36PAE: The experiment in Exercise 12.33 was redesigned so that the reaction started with 0.15 mol each of...
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When excess solid YZ is put in water and allowed to dissolve the following equilibrium reaction occurs and the equilibrium table shown can be set up. YZ(s) excess [initial] [change] [equilibrium] excess X -X = Y+ (aq) 0 +x +x + Z¯(aq) 0 +x +x The amount of solid that dissolves is called the molar solubility, denoted here by x. Since the concentration of the solid is constant and is not included in the Ksp expression, the equilibrium expression for the reaction is Ksp = [Y][Z], or, in terms of molar solubility, Ksp = x². Enter the Ksp expression for the solid AB2 in terms of the molar solubility x. Express your answer in terms of x. ► View Available Hint(s) Ksp Submit ——| ΑΣΦ ?
Transcribed Image Text:When excess solid YZ is put in water and allowed to dissolve the following equilibrium reaction occurs and the equilibrium table shown can be set up. YZ(s) excess [initial] [change] [equilibrium] excess X -X = Y+ (aq) 0 +x +x + Z¯(aq) 0 +x +x The amount of solid that dissolves is called the molar solubility, denoted here by x. Since the concentration of the solid is constant and is not included in the Ksp expression, the equilibrium expression for the reaction is Ksp = [Y][Z], or, in terms of molar solubility, Ksp = x². Enter the Ksp expression for the solid AB2 in terms of the molar solubility x. Express your answer in terms of x. ► View Available Hint(s) Ksp Submit ——| ΑΣΦ ?
Enter the the Ksp expression for C2D3 in terms of the molar solubility . Express your answer in terms of x. ► View Available Hint(s) Ksp = Submit ——| ΑΣΦ ?
Transcribed Image Text:Enter the the Ksp expression for C2D3 in terms of the molar solubility . Express your answer in terms of x. ► View Available Hint(s) Ksp = Submit ——| ΑΣΦ ?
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We need to write Ksp expressions for solid AB2 and solid C2D3 interms of molar solubility x

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