When evaluating the following integral 16dr using trigonometric substitution, Part A The correct substitution for is r=4 sec 8: Answer= (enter T=true and F=false) and dr is 4 sec 0 tan 6 d0 dr: Answer= (enter T=true and F=false) %3D Part B After evaluating the integral 1dr using trigonometric substitution., the correct anti derivative will be Va -16-4sec (x/4) +C Answer= Kenter T=true and F=false)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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When evaluating the following integral V-16r using trigonometric substitution
Part A
The correct substitution for is r = 4 sec e: Answer=
(enter T=true and F=false)
and dr is 4 sec 0 tan 0 d0
da: Answer=
(enter T=true and F=false)
Part B
After evaluating the integral 10dr using trigonometric substitution, the correct anti derivative will be
V -16-4sec '(x/4)+C
Answer=
Kenter T=true and F=false)
Transcribed Image Text:When evaluating the following integral V-16r using trigonometric substitution Part A The correct substitution for is r = 4 sec e: Answer= (enter T=true and F=false) and dr is 4 sec 0 tan 0 d0 da: Answer= (enter T=true and F=false) Part B After evaluating the integral 10dr using trigonometric substitution, the correct anti derivative will be V -16-4sec '(x/4)+C Answer= Kenter T=true and F=false)
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