pls help me When creating a right-endpoint Riemann sum on the interval [-62.3, 253.9] using 44rectangles, the 10th endpoint used to calculate the height of the approximating rectanglewould bea. 217.5909b. 9.5636c. 253.9d. -62.3e. 82.4273 100100Suppose that Σ α; = -19.2 and Σ9 b; = -6. Then what isi=1Ο a. -33.6000Ο b. -12.2000Ο c.c. 36.60d. -1Ο e. -79.60100Σ3a; – 4bii=1

Width of each rectangle Right endpoint of rectangle…

Answered: When creating a right-endpoint Riemann…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

pls help me

When creating a right-endpoint Riemann sum on the interval [-62.3, 253.9] using 44
rectangles, the 10th endpoint used to calculate the height of the approximating rectangle
would be
a. 217.5909
b. 9.5636
c. 253.9
d. -62.3
e. 82.4273

100
100
Suppose that Σ α; = -19.2 and Σ9 b; = -6. Then what is
i=1
Ο a. -33.6000
Ο b. -12.2000
Ο c.
c. 36.60
d. -1
Ο e. -79.60
100
Σ3a; – 4bi
i=1

Expert Solution

Step 1: 10th endpoint of Riemann sum.

Width of each rectangle

$equals increment x equals fraction numerator b minus a over denominator n end fraction equals fraction numerator 253.9 minus left parenthesis negative 62.3 right parenthesis over denominator 44 end fraction equals fraction numerator 316.2 over denominator 44 end fraction equals 7.18636$

Right endpoint of $i to the power of t h end exponent$ rectangle $equals a plus increment x times i$

$equals negative 62.3 plus 7.18636 cross times i$

10th endpoint

$equals negative 62.3 plus 7.18636 cross times 10 equals negative 62.3 plus 71.86 equals 9.5636$

Option b is correct.