When calling a swap function to swap the value of the two arrays, how do I add the reference to the calling statement without giving me an error? Also, I have to use pointers for this assignment. Here is the code: const int S = 10; //Pre-condition: two c strings of the same size //Post-condition: swap the values of the c strings void swapArr(char array1[ S], char array2[ S]) { int size = 0; for (int i = 0; array1[1] != '\0'; i++) { size++; } char* value = new char; value = new char [size]; //Loop fusion for (int i = 0; i < size; i++) { //Swap the values value[i] = array1[i]; array1[i] = array2[i]; array2[i] = value[i]; } } int main(){ char array1[S]= { "Hello" }; char array2[S] = { "World"}; //For some reason the swap function is not working swapArr(& array1[S], & array2[S]); for (int i = 0; array1[i] != '\0'; i++) { std::cout << array1[i]; } }
When calling a swap function to swap the value of the two arrays, how do I add the reference to the calling statement without giving me an error? Also, I have to use pointers for this assignment. Here is the code: const int S = 10; //Pre-condition: two c strings of the same size //Post-condition: swap the values of the c strings void swapArr(char array1[ S], char array2[ S]) { int size = 0; for (int i = 0; array1[1] != '\0'; i++) { size++; } char* value = new char; value = new char [size]; //Loop fusion for (int i = 0; i < size; i++) { //Swap the values value[i] = array1[i]; array1[i] = array2[i]; array2[i] = value[i]; } } int main(){ char array1[S]= { "Hello" }; char array2[S] = { "World"}; //For some reason the swap function is not working swapArr(& array1[S], & array2[S]); for (int i = 0; array1[i] != '\0'; i++) { std::cout << array1[i]; } }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
When calling a swap function to swap the value of the two arrays, how do I add the reference to the calling statement without giving me an error? Also, I have to use pointers for this assignment.
Here is the code:
const int S = 10;
//Pre-condition: two c strings of the same size
//Post-condition: swap the values of the c strings
void swapArr(char array1[ S], char array2[ S]) {
int size = 0;
for (int i = 0; array1[1] != '\0'; i++) {
size++;
}
for (int i = 0; array1[1] != '\0'; i++) {
size++;
}
char* value = new char;
value = new char [size];
//Loop fusion
for (int i = 0; i < size; i++) {
//Swap the values
value[i] = array1[i];
array1[i] = array2[i];
array2[i] = value[i];
}
value = new char [size];
//Loop fusion
for (int i = 0; i < size; i++) {
//Swap the values
value[i] = array1[i];
array1[i] = array2[i];
array2[i] = value[i];
}
}
int main(){
char array1[S]= { "Hello" };
char array2[S] = { "World"};
char array2[S] = { "World"};
//For some reason the swap function is not working
swapArr(& array1[S], & array2[S]);
for (int i = 0; array1[i] != '\0'; i++) {
std::cout << array1[i];
}
std::cout << array1[i];
}
}
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