When atoms of sodium (Na) and chlorine (Cl) combine to form salt (NaCl), the Na ion is smaller than the Na atom, while the CI ion is larger than the Cl atom. Why? 2. A The Na and Cl atoms both lost electrons. B The Na and Cl atoms both gained electrons. C The Na atom lost an electron, while the Cl atom gained an electron. D The Na atom gained an electron, while the Cl atom lost an electron.

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### Formation of Sodium Chloride (NaCl)

**Question:**
When atoms of sodium (Na) and chlorine (Cl) combine to form salt (NaCl), the Na\(^+\) ion is smaller than the Na atom, while the Cl\(^-\) ion is larger than the Cl atom. Why?

**Answer Choices:**
A. The Na and Cl atoms both lost electrons.
B. The Na and Cl atoms both gained electrons.
C. The Na atom lost an electron, while the Cl atom gained an electron.
D. The Na atom gained an electron, while the Cl atom lost an electron.

**Correct Answer:**
B. The Na and Cl atoms both gained electrons.

### Explanation:

**Option C is the correct answer.** 

When sodium (Na) and chlorine (Cl) interact to form sodium chloride (NaCl), the formation involves the transfer of electrons:

- The sodium atom (Na) loses one electron to form a sodium ion (Na\(^+\)). This loss of an electron results in the Na\(^+\) ion being smaller than the original Na atom because it now has one fewer electron and less electron-electron repulsion in its electron shell.
- The chlorine atom (Cl) gains one electron to form a chloride ion (Cl\(^-\)). This gain of an electron results in the Cl\(^-\) ion being larger than the original Cl atom due to the additional electron increasing electron-electron repulsion in its electron shell. 

This process can be summarized by the following reaction: 

\[ \text{Na} \rightarrow \text{Na}^+ + \text{e}^- \]
\[ \text{Cl} + \text{e}^- \rightarrow \text{Cl}^- \]

The resulting ionic compound, NaCl, consists of Na\(^+\) and Cl\(^-\) ions held together by ionic bonds. 

**Note:** 
Option B is highlighted in the image but it is incorrect as both atoms did not gain electrons. The proper electronic transaction involves the loss and gain of electrons by the Na and Cl atoms respectively.
Transcribed Image Text:### Formation of Sodium Chloride (NaCl) **Question:** When atoms of sodium (Na) and chlorine (Cl) combine to form salt (NaCl), the Na\(^+\) ion is smaller than the Na atom, while the Cl\(^-\) ion is larger than the Cl atom. Why? **Answer Choices:** A. The Na and Cl atoms both lost electrons. B. The Na and Cl atoms both gained electrons. C. The Na atom lost an electron, while the Cl atom gained an electron. D. The Na atom gained an electron, while the Cl atom lost an electron. **Correct Answer:** B. The Na and Cl atoms both gained electrons. ### Explanation: **Option C is the correct answer.** When sodium (Na) and chlorine (Cl) interact to form sodium chloride (NaCl), the formation involves the transfer of electrons: - The sodium atom (Na) loses one electron to form a sodium ion (Na\(^+\)). This loss of an electron results in the Na\(^+\) ion being smaller than the original Na atom because it now has one fewer electron and less electron-electron repulsion in its electron shell. - The chlorine atom (Cl) gains one electron to form a chloride ion (Cl\(^-\)). This gain of an electron results in the Cl\(^-\) ion being larger than the original Cl atom due to the additional electron increasing electron-electron repulsion in its electron shell. This process can be summarized by the following reaction: \[ \text{Na} \rightarrow \text{Na}^+ + \text{e}^- \] \[ \text{Cl} + \text{e}^- \rightarrow \text{Cl}^- \] The resulting ionic compound, NaCl, consists of Na\(^+\) and Cl\(^-\) ions held together by ionic bonds. **Note:** Option B is highlighted in the image but it is incorrect as both atoms did not gain electrons. The proper electronic transaction involves the loss and gain of electrons by the Na and Cl atoms respectively.
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