The real image formed with a mirror M1 is located 18 cm from it. The mirror M1 isreplaced by a mirror M2 with a double radius of curvature (R2 = 2xR1) whilemaintaining the object distance fixed. The new image distance can be written as:q2 = 9XR1/(R1 - 9)%3Dq2 = 18XR1/(R1 - 18)q2 = 9XR1/(9 - R1)q2 = -12XR1/(R1 - 12)O q2 = 18XR1/(18 - R1 )%3D When an object is placed 14 cm away from a concave mirror, the height of itsupright image is double its height. What is the focal length of the mirror?O f = 28/3 cmO f = 28 cmO f = 8 cmO f = 24 cmO f = -8 cm

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When an object is placed 14 cm away from a concave mirror, the height of its upright image is double its height. What is the focal length of the mirror? Of= 28/3 cm O f = 28 cm O f = 8 cm O f = 24 cm O f = -8 cm