When an object is placed 14 cm away from a concave mirror, the height of its upright image is double its height. What is the focal length of the mirror? Of= 28/3 cm O f = 28 cm O f = 8 cm O f = 24 cm O f = -8 cm
When an object is placed 14 cm away from a concave mirror, the height of its upright image is double its height. What is the focal length of the mirror? Of= 28/3 cm O f = 28 cm O f = 8 cm O f = 24 cm O f = -8 cm
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Question
![The real image formed with a mirror M1 is located 18 cm from it. The mirror M1 is
replaced by a mirror M2 with a double radius of curvature (R2 = 2xR1) while
maintaining the object distance fixed. The new image distance can be written as:
q2 = 9XR1/(R1 - 9)
%3D
q2 = 18XR1/(R1 - 18)
q2 = 9XR1/(9 - R1)
q2 = -12XR1/(R1 - 12)
O q2 = 18XR1/(18 - R1 )
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F823c1284-2399-497d-a452-eb804e54e679%2F31a72d2a-67fc-4b45-9acc-e1c5f97cf766%2Ft17mkp5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The real image formed with a mirror M1 is located 18 cm from it. The mirror M1 is
replaced by a mirror M2 with a double radius of curvature (R2 = 2xR1) while
maintaining the object distance fixed. The new image distance can be written as:
q2 = 9XR1/(R1 - 9)
%3D
q2 = 18XR1/(R1 - 18)
q2 = 9XR1/(9 - R1)
q2 = -12XR1/(R1 - 12)
O q2 = 18XR1/(18 - R1 )
%3D
![When an object is placed 14 cm away from a concave mirror, the height of its
upright image is double its height. What is the focal length of the mirror?
O f = 28/3 cm
O f = 28 cm
O f = 8 cm
O f = 24 cm
O f = -8 cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F823c1284-2399-497d-a452-eb804e54e679%2F31a72d2a-67fc-4b45-9acc-e1c5f97cf766%2Fm75dqya_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When an object is placed 14 cm away from a concave mirror, the height of its
upright image is double its height. What is the focal length of the mirror?
O f = 28/3 cm
O f = 28 cm
O f = 8 cm
O f = 24 cm
O f = -8 cm
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