When an inductor is connected to a 60.0 Hz source it has an inductive reactance of 50.2 0. Determine the maximum current in the inductor (in A) if it is connected to a 47.0 Hz source that produces a 110 V rms voltage.

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**Problem Statement: Inductor in AC Circuit**

When an inductor is connected to a 60.0 Hz source, it has an inductive reactance of 50.2 Ω. Determine the maximum current in the inductor (in Amperes) if it is connected to a 47.0 Hz source that produces a 110 V rms voltage.

**Answer:**

\[ \text{Maximum Current} (I_{\text{max}}) = \_\_\_ \text{ A} \]

*Note: There is a text box provided for the answer.*

**Explanation:**

To solve this problem, use the formula for inductive reactance (\(X_L\)):

\[ X_L = 2 \pi f L \]

Where:
- \( f \) is the frequency of the AC source
- \( L \) is the inductance of the coil

Given the existing reactance at 60.0 Hz, you can find \( L \) and then determine the new reactance at 47.0 Hz. Use Ohm's Law for AC circuits (\( V = I X_L \)) to find the current. Remember \( V \) here refers to the rms voltage, and \( I \) is the rms current related to the maximum current by \( I_{\text{max}} = \sqrt{2} \times I_{\text{rms}} \).

**Equations to Consider:**

1. \( X_L = 2 \pi f L \)
2. \( I_{\text{rms}} = \frac{V_{\text{rms}}}{X_L} \)
3. \( I_{\text{max}} = \sqrt{2} \times I_{\text{rms}} \)
Transcribed Image Text:**Problem Statement: Inductor in AC Circuit** When an inductor is connected to a 60.0 Hz source, it has an inductive reactance of 50.2 Ω. Determine the maximum current in the inductor (in Amperes) if it is connected to a 47.0 Hz source that produces a 110 V rms voltage. **Answer:** \[ \text{Maximum Current} (I_{\text{max}}) = \_\_\_ \text{ A} \] *Note: There is a text box provided for the answer.* **Explanation:** To solve this problem, use the formula for inductive reactance (\(X_L\)): \[ X_L = 2 \pi f L \] Where: - \( f \) is the frequency of the AC source - \( L \) is the inductance of the coil Given the existing reactance at 60.0 Hz, you can find \( L \) and then determine the new reactance at 47.0 Hz. Use Ohm's Law for AC circuits (\( V = I X_L \)) to find the current. Remember \( V \) here refers to the rms voltage, and \( I \) is the rms current related to the maximum current by \( I_{\text{max}} = \sqrt{2} \times I_{\text{rms}} \). **Equations to Consider:** 1. \( X_L = 2 \pi f L \) 2. \( I_{\text{rms}} = \frac{V_{\text{rms}}}{X_L} \) 3. \( I_{\text{max}} = \sqrt{2} \times I_{\text{rms}} \)
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