College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
![When an incident light ray reflects off a boundary
with a medium having a higher index of
refraction, the phenomenon is called:
O hard reflection
O soft reflection
O soft refraction
O hard refraction
Problem 3 i.
For the parts of the below question, fill in the
empty boxes with your answer (YOUR ANSWER
MUST BE ONLY A NUMBER; DO NOT WRITE
UNITS; DO NOT WRITE LETTERS).
A thin film of a material (nfm = 1.35) is
suspended within a wire frame in air, as shown in
the figure. The arrangement is illuminated by
4.8 x 10-7 m light that falls at an angle of 25" on
the surface of the film. A large region of the film
appears bright.
nair
b)
nfilm
nair
a) [
The sine of the angle of refraction
0, at the air-film interface is given by:
1.35 sin(25)
sin(25°)
1.35
9,-
c)
in the film.
Calculate 0, in degrees.
select one:
- Calculate the wavelength A, of light
d) E
The minimum thickness d of the film
is obtained for a value of m such that:
Om = 0
Om = 1
Om = 2
Om = 3
d=
T
d
1
Osin(25%)
e) i
Assume 8, = 33° and A/
4.5 x 10-7 m. Calculate d.
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88ef514f-41a9-4ed4-8128-7846ce202874%2F5b89e53d-5376-419a-803a-55e1663e7f14%2Fkgggc0a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When an incident light ray reflects off a boundary
with a medium having a higher index of
refraction, the phenomenon is called:
O hard reflection
O soft reflection
O soft refraction
O hard refraction
Problem 3 i.
For the parts of the below question, fill in the
empty boxes with your answer (YOUR ANSWER
MUST BE ONLY A NUMBER; DO NOT WRITE
UNITS; DO NOT WRITE LETTERS).
A thin film of a material (nfm = 1.35) is
suspended within a wire frame in air, as shown in
the figure. The arrangement is illuminated by
4.8 x 10-7 m light that falls at an angle of 25" on
the surface of the film. A large region of the film
appears bright.
nair
b)
nfilm
nair
a) [
The sine of the angle of refraction
0, at the air-film interface is given by:
1.35 sin(25)
sin(25°)
1.35
9,-
c)
in the film.
Calculate 0, in degrees.
select one:
- Calculate the wavelength A, of light
d) E
The minimum thickness d of the film
is obtained for a value of m such that:
Om = 0
Om = 1
Om = 2
Om = 3
d=
T
d
1
Osin(25%)
e) i
Assume 8, = 33° and A/
4.5 x 10-7 m. Calculate d.
=
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