When an incident light ray reflects off a boundary with a medium having a higher index of refraction, the phenomenon is called:

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11th Edition
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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When an incident light ray reflects off a boundary
with a medium having a higher index of
refraction, the phenomenon is called:
O hard reflection
O soft reflection
O soft refraction
O hard refraction
Problem 3 i.
For the parts of the below question, fill in the
empty boxes with your answer (YOUR ANSWER
MUST BE ONLY A NUMBER; DO NOT WRITE
UNITS; DO NOT WRITE LETTERS).
A thin film of a material (nfm = 1.35) is
suspended within a wire frame in air, as shown in
the figure. The arrangement is illuminated by
4.8 x 10-7 m light that falls at an angle of 25" on
the surface of the film. A large region of the film
appears bright.
nair
b)
nfilm
nair
a) [
The sine of the angle of refraction
0, at the air-film interface is given by:
1.35 sin(25)
sin(25°)
1.35
9,-
c)
in the film.
Calculate 0, in degrees.
select one:
- Calculate the wavelength A, of light
d) E
The minimum thickness d of the film
is obtained for a value of m such that:
Om = 0
Om = 1
Om = 2
Om = 3
d=
T
d
1
Osin(25%)
e) i
Assume 8, = 33° and A/
4.5 x 10-7 m. Calculate d.
=
Transcribed Image Text:When an incident light ray reflects off a boundary with a medium having a higher index of refraction, the phenomenon is called: O hard reflection O soft reflection O soft refraction O hard refraction Problem 3 i. For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). A thin film of a material (nfm = 1.35) is suspended within a wire frame in air, as shown in the figure. The arrangement is illuminated by 4.8 x 10-7 m light that falls at an angle of 25" on the surface of the film. A large region of the film appears bright. nair b) nfilm nair a) [ The sine of the angle of refraction 0, at the air-film interface is given by: 1.35 sin(25) sin(25°) 1.35 9,- c) in the film. Calculate 0, in degrees. select one: - Calculate the wavelength A, of light d) E The minimum thickness d of the film is obtained for a value of m such that: Om = 0 Om = 1 Om = 2 Om = 3 d= T d 1 Osin(25%) e) i Assume 8, = 33° and A/ 4.5 x 10-7 m. Calculate d. =
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