When an electron in the hydrogen atom makes a transition from an orbital with n=5 to an orbital with n=3, what is the wavelength (in nm) of the light emitted from the hydrogen atom? Round and report your answer to the nearest whole number. Don’t enter the unit in the answer box. C=3.0x10^8 m/s, h=6.626x10^-34 JxS
Atomic Structure
The basic structure of an atom is defined as the component-level of atomic structure of an atom. Precisely speaking an atom consists of three major subatomic particles which are protons, neutrons, and electrons. Many theories have been stated for explaining the structure of an atom.
Shape of the D Orbital
Shapes of orbitals are an approximate representation of boundaries in space for finding electrons occupied in that respective orbital. D orbitals are known to have a clover leaf shape or dumbbell inside where electrons can be found.
Introduction:
Given that electron is moving from n=5 to n=3. When the transition is taking from a higher energy level to a lower energy level it is called as deexcitation. Energy is released during electronic deexcitation.
The energy released in deexcitation is equal to the difference in energies of initial and final levels. Negative sign is used to indicate that the energy is released in this process.
The energy released for electronic deexcitation is given by :
Therefore energy released during this transition is 1.55 x 10-19J.
Trending now
This is a popular solution!
Learn your way
Includes step-by-step video
Step by step
Solved in 2 steps
